The equation of the straight line is y=mx+q where q is the number on the y-axis where the line passes, as you can see it is -3. It turns into:
y=mx+(-3) -> y=mx-3
Then consider a point on the line and take the coordinates, such as the point with coordinates (-2;-4), so now you know that:
x=-2 and y=-4
At this point you put these values into the equation:
y=mx-3
-4=m(-2)-3
then solve:
-4=-2m-3
-2m=+3-4
-2m=-1
m=+1/2
Put the value of m into the equation and you found it:
y=1/2x-3
Answer:
y = 8x + 14
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = -
x + 6 ← is in slope- intercept form
with slope m = - 
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= 8 , then
y = 8x + c ← is the partial equation
To find c substitute (- 3, - 10 ) into the partial equation
- 10 = - 24 + c ⇒ c = - 10 + 24 = 14
y = 8x + 14 ← equation of perpendicular line
Answer:
The Agent Would Make $24000
Step-by-step explanation:
Answer:
785 acres
Step-by-step explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Let X represent the random variable amount of corn yield
Assuming the X follows a normal distribution
And we know that the average
is dsitributed:

And we are interested on this probability:

For this case we can use the z score formula given by:

If we apply this we got:

And since we have a proportion estimated and we hava a total of 1200 acres the expected to yield more than 180 bushels of corn per acre would be:

And if we round up this amount we got
and that would be the best option for this case.