Answer:
60%
Step-by-step explanation:
55 - 22 = 33
33/55 = 0.6
0.6*100 = 60%
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
Answer:
C = 5Q
Step-by-step explanation:
C = Length of Cloth in Meters (C)
Q = Number of Quilts Made (Q)
C = 5Q
Change C for the numbers under (Length of Cloth in Meters (C))
Nad change Q for the numbers under (Number of Quilts Made (Q))
So the new equations would be:
0 = 5(0) ---------> 0 = 0
5 = 5(1) ---------> 5 = 5
10 = 5(2) ---------> 10 = 10
15 = 5(3) ---------> 15 = 15
20 = 5(4) ---------> 20 = 20
25 = 5(5) ---------> 25 = 25
So the only option that amkes sense is (C = 5Q)
Answer:
180÷12
Step-by-step explanation:
the equation currently looks like
12n=180 basically
hint answers 5
