Answer:
The regression line is not a good model because there is a pattern in the residual plot.
Step-by-step explanation:
Given is a residual plot for a data set
The residual plot shows scatter plot of x and y
The plotting of points show that there is not likely to be a linear trend of relation between the two variables. It is more likely to be parabolic or exponential.
Hence the regression line cannot be a good model as they do not approach 0.
Also there is not a pattern of linear trend.
D) The regression line is not a good model because there is a pattern in the residual plot.
Answer: B) 9
Step-by-step explanation:
You are not dumb. You just probably don't know how to solve this.
When you have the same base (3) raised to x exponent, and these bases are dividing each other, you put the same base and subtract exponents.
![\frac{3^4}{3^2}=3^4^-^2=3^2=9](https://tex.z-dn.net/?f=%5Cfrac%7B3%5E4%7D%7B3%5E2%7D%3D3%5E4%5E-%5E2%3D3%5E2%3D9)
Another way of looking at this is;
![\frac{3^4}{3^2}=\frac{3*3*3*3}{3*3} =\frac{3*3*3}{3} =\frac{3*3}{1} =3*3=9](https://tex.z-dn.net/?f=%5Cfrac%7B3%5E4%7D%7B3%5E2%7D%3D%5Cfrac%7B3%2A3%2A3%2A3%7D%7B3%2A3%7D%20%3D%5Cfrac%7B3%2A3%2A3%7D%7B3%7D%20%20%3D%5Cfrac%7B3%2A3%7D%7B1%7D%20%3D3%2A3%3D9)
Answer:
C. 37 miles
Step-by-step explanation:
0.50 + 1.50 = 20
-1.50 -1.50
0.50 = 18.50
18.50 / 0.50 = 37
Answer:
$40
Step-by-step explanation:
230/5= $46 per member
46-$6 boxed lunch= $40 remaining
Eliminate
.
![u + v = (3x - 4y) + (x + 4y) = 4x \implies x = \dfrac{u+v}4](https://tex.z-dn.net/?f=u%20%2B%20v%20%3D%20%283x%20-%204y%29%20%2B%20%28x%20%2B%204y%29%20%3D%204x%20%5Cimplies%20x%20%3D%20%5Cdfrac%7Bu%2Bv%7D4)
Eliminate
.
![u - 3v = (3x - 4y) - 3 (x + 4y) = -16y \implies y = \dfrac{3v-u}{16}](https://tex.z-dn.net/?f=u%20-%203v%20%3D%20%283x%20-%204y%29%20-%203%20%28x%20%2B%204y%29%20%3D%20-16y%20%5Cimplies%20y%20%3D%20%5Cdfrac%7B3v-u%7D%7B16%7D)
The Jacobian for this change of coordinates is
![J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} \dfrac14 & \dfrac14 \\\\ -\dfrac1{16} & \dfrac3{16} \end{bmatrix}](https://tex.z-dn.net/?f=J%20%3D%20%5Cbegin%7Bbmatrix%7D%20x_u%20%26%20x_v%20%5C%5C%20y_u%20%26%20y_v%20%5Cend%7Bbmatrix%7D%20%3D%20%5Cbegin%7Bbmatrix%7D%20%5Cdfrac14%20%26%20%5Cdfrac14%20%5C%5C%5C%5C%20-%5Cdfrac1%7B16%7D%20%26%20%5Cdfrac3%7B16%7D%20%5Cend%7Bbmatrix%7D)
with determinant
![\det(J) = \dfrac14\cdot\dfrac3{16} - \dfrac14\cdot\left(-\dfrac1{16}\right) = \dfrac1{16}](https://tex.z-dn.net/?f=%5Cdet%28J%29%20%3D%20%5Cdfrac14%5Ccdot%5Cdfrac3%7B16%7D%20-%20%5Cdfrac14%5Ccdot%5Cleft%28-%5Cdfrac1%7B16%7D%5Cright%29%20%3D%20%5Cdfrac1%7B16%7D)