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Charra [1.4K]
3 years ago
9

easy algebra question below first correct answer gets brainliest if you put a link you will be blocked and reported

Mathematics
1 answer:
Margaret [11]3 years ago
5 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of areas,

we know that, area of rectangle = length * width,

here, length = x-2 and width = x-1

hence, area = (x-2) (x-1)

==> area = x^2 -x -2x +2

==> Area = x^2 - 3x + 2

hence the Option D.) is correct

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Algebra identify the pattern. Then write the next three terms in each sequence. 63,58,53,48.....
vovikov84 [41]

Answer:43, 38, 33

Step-by-step explanation:

The pattern is subtracting 5

63 -5 = 58

58 - 5 = 53

53 - 5 = 48

48 - 5 = 43

43 - 5 = 38

38 - 5 = 33

8 0
3 years ago
What is 5.756565x 344
qaws [65]
1980.25836 is the answer
5 0
3 years ago
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What is the least common denominator for adding the fractions 4/15, 1/12, and 3/8
il63 [147K]
I think you want the least common multipule (exg LCM of 2,3,4 is 12)

so we find the factors and include all of them so like this

15=3 times 5
12=2 times 2 times 3
8=2 times 2 times 2

so to include all of them we include 3 2's, 1 3 and 1 5 or 2 times 2 times 2 times 3 times 5 or 8 times 15 or 4 times 30 or 120

the LCM is 120

so 4/15=32/120
1/12=10/120
3/8=45/120

add 32/120+10/120+45/120=(32+10+45)/120=87/120
5 0
3 years ago
Read 2 more answers
An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t
erastova [34]

Answer:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

\bar X=46.5 represent the mean

\sigma=1.1 represent the population standard deviation

n=150 sample size  

\mu_o =46.7 represent the value to verify

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:\mu = 46.7  

Alternative hypothesis:\mu \neq 46.7  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing we got:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0
3 years ago
Please help me for 50 points
lidiya [134]

Answer:

why why why humm why why why why

4 0
3 years ago
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