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Charra [1.4K]
3 years ago
9

easy algebra question below first correct answer gets brainliest if you put a link you will be blocked and reported

Mathematics
1 answer:
Margaret [11]3 years ago
5 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of areas,

we know that, area of rectangle = length * width,

here, length = x-2 and width = x-1

hence, area = (x-2) (x-1)

==> area = x^2 -x -2x +2

==> Area = x^2 - 3x + 2

hence the Option D.) is correct

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How do you do this question?
vaieri [72.5K]

Answer:

(-∞, -2), (-2, -0.618), and (1.618, 3)

Step-by-step explanation:

The red plus (+) signs indicate the regions in which the function is concave up, and the red negative (-) signs indicate the regions in which the function is concave down.

Note that the sign of the concavity changes at an inflection point.

Let's examine the intervals given.

(-∞, -2): Yes, concave up.

(-∞, -1.17): No. Concave up in (-∞, -2) but concave down in (-2, -1.17).

(-2, 0): No. Concave down in (-2, -1.17) but increasing in (-1.17, 0.0).

(-1.17, 0.689): Yes. Concave up.

(-0.618, 1.618): No. Concave up in (-0.618, 0.689) but concave down in (0.689, 1.618).

(0, 3): No. Concave up in (0, 0.689), concave down in (0.689, 2.481), and concave up in (2.481, 3).

(2.481, ∞): Yes. Concave up.

The three intervals that are concave up are (-∞, -2), (-1.17, -0.689), and (2.481, ∞).

4 0
3 years ago
WHICH IS NOT A LINEAR FUNCTION ​
Tom [10]

Answer:

OPTION C

Step-by-step explanation:

IN OPT. A- 2 IS MULTIPLED IN EACH NO.

IN OPT.B-2 IS MULTIPLED

IN OPT.D-1 IS ADDED

IN OPT.E-2 IS ADDED

4 0
2 years ago
describe what would be true about the rate of change in a situation that could be represented by a graphed line and an equation
Andru [333]
If y=mx+b,

\frac { dy }{ dx } =m

You can't differentiate a constant, so dy/dx=m.
5 0
3 years ago
Answer this right for a cookie
elena55 [62]
Ouuuuuuuuuu I want a cookie
6 0
3 years ago
What is the domain of f?
lana [24]

Answer: C) All real values of x such that x \le 0

In other words, x must be 0 or smaller.

===================================================

Explanation:

The reason why is because we must make the stuff under the square root to never be negative. We must make -2x be 0 or larger.

So,

-2x \ge 0 \\\\-2x+2x \ge 0+2x \ \text{ ... add 2x to both sides}\\\\0 \ge 2x\\\\2x \le 0  \ \text{ ... flip both sides, and the inequality sign}\\\\x \le 0/2  \ \text{ ... divide both sides by 2}\\\\x \le 0

As an example, if x = -2, then -2x = -2(-2) = 4 is positive. Applying the square root to a positive number is valid.

But if x = 5, then -2x = -2*5 = -10 is under the square root, which is not allowed.

3 0
3 years ago
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