A rectangle has an area of 12 feet and a length of 5 feet .what is its width
2 answers:
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Answer:
Subtract 5x from both sides of the equation.
7y=1−5x
x+4y=−5
Divide each term by 7 and simplify.
y=17−5x/7
x+4y=−5
Subtract x from both sides of the equation.
y=1/7−5x/7
4y=−5−x
y=1/7−5x/7
Divide each term by 4 and simplify.
y=1/7−5x/7
y=−5/4−x/4
y=1/7−5x/7
Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution. (3,−2)
Step-by-step explanation:
