All categories

3 years ago

If a spring stretches 0.8 with 20 pounds attached how far will it stretch with 60 pounds attached?

2 answers:

3 0

$\bf \begin{array}{ccll} length&lbs\\ \cline{1-2} 0.8&20\\ x&60 \end{array}\implies \cfrac{0.8}{x}=\cfrac{20}{60}\implies \cfrac{0.8}{x}=\cfrac{1}{3}\implies 2.4=x$

Scilla [17]3 years ago

3 0

2.4 because for it to stretch one pound its .04 so
.04•60=2.4

You might be interested in

Describe the association for this scatterplot.

seropon [69]

Positive association

5 0

3 years ago

Read 2 more answers

Write the equation of the line that is parallel to the given segment and that passes through the point (-3,0).

grandymaker [24]

Answer:

Option (B)

Step-by-step explanation:

In the figure attached,

A straight line is passing through two points (0, 2) and (3, 1).

Slope of this line ( $m_1$ ) = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{2-1}{0-3}$

= $-\frac{1}{3}$

Let the slope of a parallel to the line given in the graph = $m_2$

By the property of parallel lines,

$m_1=m_2$

$m_2=-\frac{1}{3}$

Equation of a line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of the parallel line which passes through (-3, 0) and having slope = $-\frac{1}{3}$ will be,

$y-0=-\frac{1}{3}(x+3)$

$y=-\frac{1}{3}x-1$

Option (B). will be the answer.

5 0

3 years ago

5(2x)to the third power

kumpel [21]

(5(2x))^3
Use the property of exponents:
(5^3)*(2x)^3
Simplify the exponents:
125*8*x^3
Simplify the numbers and multiply the integers:
1000*x^3

Hope this helps :)

5 0

3 years ago

What is 782,943 rounded to the nearest ten thousand

Effectus [21]

The answer is 780,000

3 0

3 years ago

Read 2 more answers

5•9-10<br> ————<br> 5-(-2).

Alenkinab [10]

Answer:

35/7 or 5

Step-by-step explanation:

so you multiply 5 and 9 which is 45- 10 which is 35 but then its 5-(-2) which when doing this a variable minus a negative makes it a positive so then its 5+2 which is 7 then you have 35/7 or 5

4 0

3 years ago