If a spring stretches 0.8 with 20 pounds attached how far will it stretch with 60 pounds attached?

2 answers:

3 0

$\bf \begin{array}{ccll} length&lbs\\ \cline{1-2} 0.8&20\\ x&60 \end{array}\implies \cfrac{0.8}{x}=\cfrac{20}{60}\implies \cfrac{0.8}{x}=\cfrac{1}{3}\implies 2.4=x$

Scilla [17]3 years ago

3 0

2.4 because for it to stretch one pound its .04 so
.04•60=2.4

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Step-by-step explanation:

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$(a) \: \frac{4}{5} \: of \: d = \frac{4}{5} d \\ \\ (b) \: \frac{3}{4} \: of \: d = \frac{3}{4} d \\ \\ (c) \: \frac{4}{5} d - \frac{3}{4} d = 1.5 \\ \\ \therefore \: \bigg(\frac{4}{5} - \frac{3}{4} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{4 \times 4 - 3 \times 5}{5 \times 4} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{16- 15}{20} \bigg) d = 1.5 \\ \\ \therefore \: \bigg(\frac{1}{20} \bigg) d = 1.5 \\ \\ \therefore \: d = 1.5 \times 20 \\ \\ \: \: \: \: \: \huge \orange{ \boxed{{ \therefore \: d = 30}}}$