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Alona [7]
3 years ago
12

Select all the measurements that are equivalent to 48 centimeters.

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0
The same thing divide all
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Please help!<br> Write down the correct type of angle for angles A to E.
mel-nik [20]

Answer:

Angle A- Obtuse angle

Angle B- Right angle

Angle C- Reflex angle

Angle D- Reflex angle

Angle E- Acute angle

4 0
3 years ago
Which shows one way to determine the factors of x^3 – 12x^2 – 2x + 24 by grouping?
krek1111 [17]
x^3-12x^2-2x+24=x^2\cdot x-x^2\cdot12-2\cdot x-2\cdot(-12)\\\\=\underline{x^2(x-12)-2(x-12)}=(x-12)(x^2-2)\\\\Answer:\boxed{d}
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3 years ago
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PLEASE HELP!! What are the explicit equation and domain for a geometric sequence with the first term of 3 a second term of -9?
frutty [35]

Answer:

The correct answer is c.

4 0
3 years ago
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Two parallel lines are crossed by a transversal.
nadya68 [22]

Answer:

Option B) y = 50

Step-by-step explanation:

We are given the following information:

Two parallel lines are crossed by a transversal.

The attached image shows the intersection of transversal and the angles.

As clear from the image, the given pair of angles form alternate interior angles.

If two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent or equal

Thus, y = 50 degree

3 0
3 years ago
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The figure is a square. Find the length of side x in simplest radical form with a rational denominator.
nika2105 [10]

Answer:

10\sqrt{2}

Step-by-step explanation:

The diagonal of any square with side length s is equal to s\sqrt{2}. Since the side length of the square is 10, the diagonal must be \boxed{10\sqrt{2}}.

To support and prove this:

The diagonal creates two 45-45-90 triangles, with the diagonal being the hypotenuse of both of these triangles. The Pythagorean Theorem states that in any triangle, the sum of the squares of both legs is equal to the square of the hypotenuse (a^2+b^2=c^2).

Call the diagonal d. In these two triangles, both legs are equal to 10 (the side lengths of the square), and the hypotenuse is the diagonal. Thus, we have:

10^2+10^2=d^2,\\100+100=d^2,\\d^2=200,\\d=\sqrt{200}=\sqrt{100}\cdot \sqrt{2}=\boxed{10\sqrt{2}}

4 0
3 years ago
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