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Natali5045456 [20]
3 years ago
5

What are the zeros of , where ? help please need some help someone help please

Mathematics
1 answer:
Crank3 years ago
4 0

{ \boxed{\boxed{\begin{array}{cc} \maltese  \bf \: given \\  \\  \rm \: f(x) = ( {x}^{2}  + 16)( {x}^{2} - 9) \\  \\  \bf \: for \: zeroes \\  \\ \pink{ \boxed{\boxed{\begin{array}{c | c}   \bf \:  {x}^{2} + 16 = 0 & \bf \: {x}^{2}  - 9 = 0 \\  \\  =  >  {x}^{2}  =  - 16& {x}^{2}  = 9 \\  \\  =  > x =  \pm \sqrt{ - 16} &x =  \pm \:  \sqrt{9}  \\  \\  =  > x =  \pm \sqrt{ {i}^{2}  {4}^{2} } &x =  \pm \:  \sqrt{ {3}^{2} } \\  \\  =  > x =  \pm \: 4i&x =  \pm3  \end{array}}}}   \\  \\  \rm \: x =  \pm3 \: and \pm \: 4i\end{array}}}}

Option A is the correct answer

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Answer:

  5/9

Step-by-step explanation:

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The desired ratio is ...

  males/total present = 60/108 = 5/9

7 0
3 years ago
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azamat

Answer to your Question:

- The Minimum Value will be 0

and

- The Maximum Value will be 30

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5 0
3 years ago
The minute had of a clock is 8 in. long.
DaniilM [7]

Answer:

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Step-by-step explanation:

Let Distance travelled be P

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Lenth of minute hand be l

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3 0
3 years ago
What values of x satisfy the equation 2x^2 -3x +4 =0
BaLLatris [955]

Answer:

(3 ± √23 * i) /4

Step-by-step explanation:

To solve this, we can apply the Quadratic Equation.

In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)

Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4

Plugging these values into our equation, we get

x = (-b ± √(b²-4ac))/(2a)

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= (3 ± √(9-32))/4

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6 0
3 years ago
I need the x and the y y I need the explication
stiv31 [10]

Step-by-step explanation:

(3x-11)+(2x+11)+2y = 180

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8 0
3 years ago
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