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ella [17]
3 years ago
15

2 + 2 =????????????????????????????????? BLAH

Mathematics
2 answers:
svetoff [14.1K]3 years ago
7 0

Answer:

4 lol

Step-by-step explanation:

free point

Irina18 [472]3 years ago
5 0

Answer:

answer: 2 + 2 = 4

Lol!!!!!!!

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M=3 and the y-intercept is (0,2)
andreev551 [17]
If you are asking for the formula thing, it is

y=3x+2
3 0
4 years ago
Can I please have some HELP!!! (Brainllest)
Solnce55 [7]

Answer:

its the last one I think.

3 0
3 years ago
A sign in front of a diving board says, "You must be 40 inches tall to dive." What percentage of this height is 34 inches?
galina1969 [7]

Answer:

85%

Step-by-step explanation:

\frac{34}{40}*\frac{100}{1}=\frac{3400}{40}=85

What I did here was multiply 34/40 by 100 to get 3400/40 or 85%.

5 0
3 years ago
Match each quadratic equation with the best way to solve it.
zzz [600]

5x^2 + 12x + 3 = 0 would best be solved by using the quadratic formula. This is because it does not factor nicely and the lead coefficient makes it hard to use the square roots method or the completing the square method.

x^2 - 4x = 8 would best be solved with the completing the square method. This is because the first step in completing the square is to put the constant on the opposite side, which is already done for you in this one.

4x^2 - 25 = 0 would best be solved with the square root method. This is because there are only two terms, they are separated by a subtraction symbol, and both are perfect squares.

x^2 - 5x + 6 would best be solved by factoring. This is the case because it is easy to find factors of the constant that add up to the x coefficient (which is what you need to factor). In this case -2 and -3 multiply to 6 and add up to -5.

4 0
4 years ago
Determine the type and number of solutions of x^2 + 10x − 25 = 0. A two real solutions B one real solution C two imaginary solut
klemol [59]

Answer:

two real solution

Step-by-step explanation:

x^2 + 10x − 25 = 0

we can solve this by finding out the value of x

lets assume the equation is   a\times x^{2}+b\times x+c=0

x=-b\pm \sqrt{(b^{2}-4ac)}\div 2a

x=-10\pm\sqrt{100+4*25}\div2

x=-5\pm5\sqrt2

then we get both real value of x

so two real solution

4 0
4 years ago
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