Question

HELP ME ASAP!!

Answer 1

Answer:

$\huge A (n) = 5 ({2})^{n - 1}$

Step-by-step explanation:

The nth term of a geometric sequence is given by

$A(n) = a _ 1( {r})^{n - 1}$

a1 is the first term

r is the common ratio

From the question we have the final answer as

$A (n) = 5 ({2})^{n - 1}$

Hope this helps you