The value of h(t) when
is 10.02.
Solution:
Given function 
To find the value of h(t) when
:

Substitute
in the given function.


Now multiply the common terms into inside the bracket.

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

To make the denominator same, take LCM of the denominators.
LCM of 64 and 32 = 64




= 10.02

Hence the value of h(t) when
is 10.02.
Answer:
-11
Step-by-step explanation:
Answer:
sorry I'm too nood for that
Answer:
Step-by-step explanation:true by multiplying 6x7=42
Answer:
517
Step-by-step explanation:
The radius of a circle is just half of the diameter (1/2d = r)
1034/2 = 517