3 years ago

144kg in the ratio 1:3:5

1 answer:

4 0

Total ratio is 1 + 3 + 5 = 9

Share for 1 = 1/9 × 144
= 16kg
Share for 3= 3/9 × 144
= 48kg
Share for 5= 5/9 × 144
= 80kg

Proof= 80 + 48 + 16 =144

You might be interested in

Below are two parallel lines with a third line intersecting them.<br> I need help solving for x

kvv77 [185]

Answer:

its a 50 degree angle i think.

Step-by-step explanation:

its a smaller size in scale of the bigger one.

6 0

4 years ago

Read 2 more answers

The inventory of a store 2 years ago was worth $45,000. This year it is worth $49,500. What is the percent increase?

UkoKoshka [18]

It is 0.4500% hope this helps

7 0

3 years ago

What is an integer in math

4vir4ik [10]

Answer:

An integer is any negative or positive number that’s not a fraction. Ex: 1, -3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Zero and negative exponentswrite in simplest for without zero or negative exponents- 17 ⁰

Valentin [98]

$-17^0=(-17)^0=1$ $\begin{gathered} (-2)^2\times(-2)^{-5}=(-2)^{2-5} \\ =(-2)^{-3} \\ =\frac{1}{(-2)^3} \\ =\frac{1}{-8} \end{gathered}$

Thus, the final answers are 1 and -1/8.

4 0

1 year ago

Given: ΔАВС, m∠ACB = 90°,m∠ACD = 30°,AD = 8 cm. Find: CD, Perimeter ΔABC <br><br> Please solve!

sukhopar [10]

If m ACD = 30 => m DCB = 60.
In triangle ACD:
$sin 30^{o}=sin \frac{AD}{AC} =\ \textgreater \ \frac{1}{2} = \frac{8}{AC} =\ \textgreater \ AC=16
$
$CD= 8 \sqrt{3}$
$BC= 16\sqrt{3}$
AC^{2}+CB^{2}=AB^{2} => AB= $\sqrt{1024}$ =32.
=> P=16+32+ $16 \sqrt{3}$ =48 + $16 \sqrt{3}$ .

8 0

4 years ago

144kg in the ratio 1:3:5​

144kg in the ratio 1:3:5