Answer:

Step-by-step explanation:
The fish population after t years can be modeled by the following equation:

In which F(0) is the initial population and r is the constant rate of decay.
Year one the fish population was 18000
This means that 
In year three the fish population was 8000 fish.
Two years later, so 






So

The common ratio in a geometric sequence is the ratio between 2 consecutive terms:
-8/2=-4,
then the sequence is 2, -8, 32, -128, -512, 2048, ...
let

be the nth term of the sequence, then




.
.
.
so clearly

and, clearly n are integers >0, since we have a 1st term, a second term and so on... of a sequence (we do not have a "zero'th term"!
Answer:
<span>C. an=2(-4)^n-1; all integers where n>0</span>
Answer: 31 hope this helped
Step-by-step explanation: I'm assuming your problem looks like this: 4+5*6-3 =? To solve this problem you need to use the order of operations. PEMDAS which stands for Parentheses, exponents, multiply and divide, and lastly add and subtract. You must multiply and divide before you add and subtract so you must do 5*6 first. You now get 4+30-3. Now all you have left is addition and subtraction so you now just go from right to left and do one at a time. So 4+30 = 34 , 34-3=31. Therefore your answer should be 31. Hope that helped!
Answer:
3x + 11
Step-by-step explanation:
Remember BPEMDAS.
"Three times a number" is saying multiply 3 times a variable; in this case, <em>x</em>. So we have 3x
"The sun of 3x and 11" is saying add our 3x and 11, so: 3x + 11