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earnstyle [38]
3 years ago
5

A rectangular container is 12cm long, 11cm wide and 10cm high. The container is filled with water to a depth of 8cm. A metal sph

ere of radius 3.5 cm is placed in the water and sinks to the bottom. Calculate the rise in water level, giving your answer in 3 significant figures.
Please can you show workings out? Many thanks
Mathematics
1 answer:
Rainbow [258]3 years ago
3 0
1) Initial volume of water inside the container: V1

V1 = 12cm*11cm*8cm = 1056 cm^3

2) Volumen of the sphere: V2

V2 = [4/3]π(r^3) = [4/3]π(3.5cm)^3 = 179.59 cm^3

3) Volume of the water plus the sphere: V3

V3 = V1+V2 = 1056 cm^3 +179.59cm^3 = 1,235.59 cm^3

4) Final level of the water inside the container: h

h = 1,239.59cm^3 / (12cm*11cm) = 9.36 cm

 

 
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Given r(x) = 11/ (x - 42)
julsineya [31]

For a given function f(x) we define the domain restrictions as values of x that we can not use in our function. Also, for a function f(x) we define the inverse g(x) as a function such that:

g(f(x)) = x = f(g(x))

<u>The restriction is:</u>

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<u>The inverse is:</u>

y = 4 + \sqrt{\frac{11}{x} }

Here our function is:

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We know that we can not divide by zero, so the only restriction in this function will be the one that makes the denominator equal to zero.

(x - 4)^2 = 0

x - 4 = 0

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So the only value of x that we need to remove from the domain is x = 4.

To find the inverse we try with the general form:

g(x) = a + \sqrt{\frac{b}{x} }

Evaluating this in our function we get:

g(f(x)) = a + \sqrt{\frac{b}{f(x)} }  = a + \sqrt{\frac{b*(x - 4)^2}{11 }}\\\\g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4)

Remember that the thing above must be equal to x, so we get:

g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4) = x\\\\{\frac{b}{11 }} = 1\\{\frac{b}{11 }}*4 - a = 0

From the two above equations we find:

b = 11

a = 4

Thus the inverse equation is:

y = 4 + \sqrt{\frac{11}{x} }

If you want to learn more, you can read:

brainly.com/question/10300045

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Step-by-step explanation:

If you want to learn more about this concept, it's called composition of functions.

First, you plug in g(x) as if it were x into f(x).

f(g(x))= -5 (1/2x + 4) + 2

= -5/2x - 20 + 2

= -5/2x - 18

Then, plug in the value given, as x.

= -5/2 (12) - 18

= -30 - 18

= - 48

I hope this helped!

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3 years ago
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