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earnstyle [38]
3 years ago
5

A rectangular container is 12cm long, 11cm wide and 10cm high. The container is filled with water to a depth of 8cm. A metal sph

ere of radius 3.5 cm is placed in the water and sinks to the bottom. Calculate the rise in water level, giving your answer in 3 significant figures.
Please can you show workings out? Many thanks
Mathematics
1 answer:
Rainbow [258]3 years ago
3 0
1) Initial volume of water inside the container: V1

V1 = 12cm*11cm*8cm = 1056 cm^3

2) Volumen of the sphere: V2

V2 = [4/3]π(r^3) = [4/3]π(3.5cm)^3 = 179.59 cm^3

3) Volume of the water plus the sphere: V3

V3 = V1+V2 = 1056 cm^3 +179.59cm^3 = 1,235.59 cm^3

4) Final level of the water inside the container: h

h = 1,239.59cm^3 / (12cm*11cm) = 9.36 cm

 

 
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Answer:

The standard error of the sample proportion is closest to 1%

Step-by-step explanation:

Standard error of the sample proportion is given as

σₓ = √[p(1-p)/n]

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σₓ = √[p(1-p)/n]

σₓ = √[0.23×0.77/2500]

σₓ = 0.0084166502 = 0.00842

σₓ = 0.00842 = 0.842%

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4 years ago
Can someone help me work out this please A and B
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Answer:

see explanation

Step-by-step explanation:

(a) (i)

x² - 9 ← is a difference of squares and factors as

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(ii)

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The factors are + 4 and - 3, since

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(iii)

Express the numerator/ denominator in factored form

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Let the number of Beta and VHS tapes be x and y respectively;

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Read more on simultaneous equations;

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