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3 years ago

Can someone help me with this page please.

Mathematics

2 answers:

LenaWriter [7]3 years ago

6 0

Answer:

1) positive

2) zero

3) positive

4) negative

5) negative

6) negative

7) 9

8) -5

9) 5

10) -23

11) -20

12) -20

13) 4,500- 4,800

Dmitriy789 [7]3 years ago

5 0

Answer:

Going by the rule stated on top of the paper:

Positive; |-3| < |5|
Zero; $16+(-16)= 16 - 16 =0$
Positive; Both numbers are positive.
Negative; |-150| > |125|
Negative; |-11| > |4|
Negative; Both numbers are negative.

$17+(-6)= 17-6= 11$

$-8 + 3 = -5$

$9+(-4)=9-4=5$

$-13+(-10)=-13-10=-23$

$-12+(-8)= -12-8=-20$

$-5+(-15)=-5-15=-20$

And for the last question, it would be $4,500 -4,800$ , but since the question asks for an addition sentence, it would be: $4500+(-4800)$

Hope this helps, brainilest is appreciated.

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Solve the inequality 29-2(3-5w) 13

valentinak56 [21]

Answer:

29-2(2w)13

29-2(26w)

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7 0

3 years ago

Help help I don’t really get this???

insens350 [35]

Answer:

Question 4: $y=\displaystyle -\frac{4}{5}x$

Question 5: $y=-5x-3$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope of the line and b is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).

Question 4

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$ where two points that pass through the line are $(x_1,y_1)$ and $(x_2,y_2)$

In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:

$\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}$

Therefore, the slope of the line is $\displaystyle -\frac{4}{5}$ . Plug this into $y=mx+b$ as the slope (m):

$y=\displaystyle -\frac{4}{5}x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (b) is 0. Plug this into $y=\displaystyle -\frac{4}{5}x+b$ :

$y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x$

Question 5

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:

$\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5$

Therefore, the slope is -5. Plug this into $y=mx+b$ :

$y=-5x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (b) is -3. Plug this into $y=-5x+b$ :

$y=-5x+(-3)\\y=-5x-3$