Answer:
x = 9
Step-by-step explanation:
6 × 9 = 54
54 + 15 = 69, which is less than 70.
Answer:
Step-by-step explanation:
To solve for degrees: (180°/π) * radians
To solve for radians: (π/180°) * degrees
Answer:
95% off
Step-by-step explanation:
because the percent u times by the actual price is the percent u have off
Answer:
C. (Chanterelle mushrooms cost less by $0.90)
Step-by-step explanation:
Divide 11.25 by 2/3, for the total amount of pound for the Cremini.
Do the same thing for Chanterelle, but the numbers given for it.
We than find out that Cremini=16.87, and Chanterelle=15.98
Now that we know Cremini is more that Chanterelle, we need to find the difference, by subtracting The bigger number by the smaller number.
Our answer is 0.89, but we will round it to 0.90.
Now we know that the Cremini costs more by $0.90, and the Chanterelle costs less by $0.90
Answer:
The probability that the restaurant can accommodate all the customers who do show up is 0.3564.
Step-by-step explanation:
The information provided are:
- At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
- If the probability of a party not showing up is 0.04.
- Assuming independence.
Let <em>X</em> denote the number of parties that showed up.
The random variable X follows a Binomial distribution with parameters <em>n</em> = 53 and <em>p</em> = 0.96.
As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.
Compute the probability that the restaurant can accommodate all the customers who do show up as follows:
![P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564](https://tex.z-dn.net/?f=P%28X%5Cleq%2050%29%3D1-P%28X%3E50%29%5C%5C%3D1-P%28X%3D51%29-P%28X%3D52%29-P%28X%3D53%29%5C%5C%3D1-%5B%7B53%5Cchoose%2051%7D%280.96%29%5E%7B51%7D%280.04%29%5E%7B53-51%7D%5D-%5B%7B53%5Cchoose%2052%7D%280.96%29%5E%7B52%7D%280.04%29%5E%7B53-52%7D%5D%5C%5C-%5B%7B53%5Cchoose%2053%7D%280.96%29%5E%7B53%7D%280.04%29%5E%7B53-53%7D%5D%5C%5C%3D1-0.27492-0.25377-0.11491%5C%5C%3D0.3564)
Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.