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4 years ago

HELP PLEASE‼️

Mathematics

1 answer:

sladkih [1.3K]4 years ago

3 0

16.8 years? sorry if this is wrong. I just divided 4% by the principal amount.

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In this question, use CAN $1.00 = JA $72.00.

Len [333]

CAN $1.00 = JA $72.00

1) 72.00(25.00) = 1800
CAN $25.00 = JA $18.00

2) 30,000.00/72 = 416.67
JA $30,000.00 = CAN $416.67

3 0

3 years ago

James age is 3 years less than twice Tori's age the sum of their ages is 30 find their ages

blagie [28]

Error// Error// Error// Error// Error// Error//

7 0

3 years ago

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

4 years ago

A square garden has a diagonal of 34 ft. Colton wants to put a fence around the entire garden.

andreyandreev [35.5K]

Let x be the side of your square. Use Pythagoras to find the side in the right triangle formed with 2 sides and the diagonals:

x² + x² = 34²

2x² = 34² = 1126

x² = 1126/2 = 578
and x =√578 = 17√2 ≈ 24 ft
H will need 24 x 4 = 96 ft

4 0

3 years ago

Read 2 more answers

Which is a set of collinear points and which statement describes the drawing. Can someone help?

Reptile [31]

First exercise:

Two points are collinear if they lie on the same line. So, option A is correct, because I, H and G all lie on the same line.

Second exercise:

Opposite rays start from the same point and go in two opposite direction. So, Option B is correct, because the rays defined by the other options always have a point in common, so they actually are opposite rays. Also, YW and YX are the same ray, because they start from the same point and continue in the same direction.

6 0

3 years ago