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2 years ago

What is value of x?

Mathematics

2 answers:

miss Akunina [59]2 years ago

7 0

Answer:

Step-by-step explanation:

Verified correct with test results.

inysia [295]2 years ago

4 0

X=27
Hopefully this helped

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Two thirds a number plus 4 is 7

Sergio039 [100]

(2/3)x+4= 7

Subtract 4 from both sides
(2/3)x= 3

Divide both sides by 2/3. To divide by a fraction, multiply the first number by the reciprocal of the second.
3*3/2= 9/2

Final answer: 9/2 or 4.5

7 0

2 years ago

Which is the equation of a line that has a slope of -2/3 and passes through point (-3, -1)? y=-2/3x+1.

bazaltina [42]

Answer:

y = -2/3x - 3

Step-by-step explanation:

First, write the equation using the slope. It should look like this: y = -2/3x + b. Next, find the y intercept by plugging in the point. This is what it looks like: -1 = -2/3(-3) + b. Multiply -2/3 by -3 to get 2. This is what it should look like now: -1 = 2 + b. Subtract 3 from both sides to get -3 = b. Go back to your original equation and plug in -3 for b. This is your final equation:

y = -2/3x - 3

Hope this helped! :)

7 0

2 years ago

A person borrows $50000 loan from bank at a rate of 10% for 5 years compounded yearly.

Hatshy [7]

<h3>Given:</h3>

P= $50,000
R= 10%
T= 5 years

P= Principal amount
R= Rate of interest
T= Time period

<h3>Solution:</h3>

$\large\boxed{Formula: A= P(1+ \frac{R}{100}{)}^{T}}$

Let's substitute according to the formula.

$A= 50000(1+ \frac{10}{100}{)}^{5}$

A= $80525.5

Now, we can find the interest paid

$\large\boxed{I= A-P}$

We'll have to deduct the total amount from the principal amount.

Let's substitute according to the formula.

$I= 80525.5-50000$

I= $30525.5

Hence, the total amount paid after 5 years is $80525.5 and $30525.5 was paid as interest.

7 0

1 year ago

How did he get this 1/2i ? I dont remember studying this definition in calc 1 neither calc 2!

Hitman42 [59]

The $i$ in the denominator is missing in the second expression. It should be

$\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}$

This follows from

$e^{iat}=\cos at+i\sin at$
$e^{-iat}=\cos at-i\sin at$
$\implies e^{iat}-e^{-iat}=2i\sin at$
$\implies \sin at=\dfrac{e^{iat}-e^{-iat}}{2i}$

8 0

2 years ago

Can someone help me with all of these

vazorg [7]

7. = 29/9 0.6 terminating
8. = 301/20 0.75 terminating

6 0

2 years ago