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tatuchka [14]
3 years ago
6

Circumference of a circle that has 5m

Mathematics
1 answer:
MrRa [10]3 years ago
5 0

Answer:

15.7 i think disksksksk

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Tony bowled 135 and 145 in his first two games. write and solve a compound inequality to find the possible values for a third ga
stira [4]
The average has to be at least 120 and at most 130
To calculate the average we need the sum of all values divided by the number of values, in this case, three (135, 145 and the third result).
120 ≤ (135 + 145 + n)/3 ≤ 130

In inequalities like this, what we change in one side, must be changed in the othe rside as well.
360 ≤ 280 + n ≤ 390
80 ≤ n ≤ 110

5 0
3 years ago
The sum of two consecutive numbers is 89. What are the two numbers? A. 43 and 46 B. 44 and 45 C. 38 and 51 D. 45 and 46
Nina [5.8K]

Answer:

C

Step-by-step explanation:

Its C

3 0
3 years ago
ILL GIVE U 20 POINTS AND BRAINLIEST, pls hurry!
serious [3.7K]

Answer:

(1/2,5)

Step-by-step explanation:

4 0
3 years ago
What is the y-intercept of the line represented by y = 4x?​
Brut [27]

Answer: 0

Step-by-step explanation: In order to identify the <em>y-intercept</em> of this equation, we want to get this equation into slope-intercept form which is more commonly known as y = mx + b form.

The problem is our equation doesn't match up quite so well with the formula y = mx + b. Our slope or <em>m</em> which is represented by the coefficient of the <em>x</em> <em>term</em> is clearly +4 but what is our y-intercept or b?

Well y = 4x can be thought of as y = 4x + 0 so you can see that our b or y-intercept equals 0.

5 0
3 years ago
What is the equation of the following graph in vertex form? parabolic function going down from the left through the point negati
Anestetic [448]
A parabolic function's key characteristic is either having 2 x-intercepts or 2 y-intercepts. That is the reason why the standard form of parabolic functions are:

(x-h)^2 = +/- 4a(y-k) or (y-k)^2 = +/- 4a(x-h), where

(h,k) is the coordinates of the vertex
4a is the lactus rectum
a is the distance from the focus to the vertex

This is also called vertex form because the vertex (h,k) is grouped according to their variable.
 
Since we don't know any of those parameters, we'll just have to graph the data points given as shown in the picture. From this data alone, we can see that the parabola has two x-intercepts, x=-4 and x=-2. Since it has 2 roots, the parabola is a quadratic equation. Its equation should be

y = (x+4)(x+2)
Expanding the right side
y = x²+4x+2x+8
y = x²+6x+8
Rearrange the equation such that all x terms are on one side of the equation
x²+6x+___=y-8+___
The blank is designated for the missing terms to complete the square. Through completing the squares method, you can express the left side of the equation into (x-h)² form. This is done by taking the middle term, dividing it by two, and squaring it. So, (6/2)²=9. Therefore, you put 9 to the 2 blanks. The equation is unchanged because you add 9 to both sides of the equation.

The final equation is 
x²+6x+9=y-8+9
(x+3)²=y+1

6 0
3 years ago
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