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Nutka1998 [239]
4 years ago
9

Team A and team B play a series. The first team to win three games wins the series. Each team is equally likely to win each game

, there are no ties, and the outcomes of the individual games are independent. If team B wins the second game and team A wins the series, what is the probability that team B wins the first game?

Mathematics
1 answer:
andrezito [222]4 years ago
7 0

Answer:

Probability is \frac{1}{4}

Step-by-step explanation:

This problem can be easily done tree diagram.

Few things keep in mind :

  • From starting of match three victories of A.
  • Less then or equal to two victories of B.
  • In each matches there are two possibilities either favourable for A or B.

First case if A wins first match

  1.       two victories of B then two of A
  2.       victory of B then A then B then A
  3.       victory of B then A then A

Second case if B wins first match(favorable)

  1.      victory of two B then three A

So total cases are 4 and favorable is one

  probability=\frac{1}{4}

[Tree diagram is in attachment]

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