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grin007 [14]
3 years ago
11

According to the scale on a map, 1 inch on the map = 15 miles. How many miles are represented by 2.5 inches on the map?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
7 0
2.5 times 15 equals 37.5 miles
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Can anybody help me???​
Tasya [4]

#10

\\ \rm\longmapsto 0

#11

  • Last three i.e Option B,C,D

#13

It started from negative ends at positive hence

\\ \rm\longmapsto y=-|x|+2

#14

  • (-3,-10)

\\ \rm\longmapsto 2(-3)-(-10)=4

\\ \rm\longmapsto -6+10=4

  • Proved

#15

  • (1,1)

\\ \rm\longmapsto 1=(1-2)^2=(-1)^2=1

#16

  • (2,-4)

\\ \rm\longmapsto -2-2(-4)>3

\\ \rm\longmapsto -2+8>3

\\ \rm\longmapsto 6>3

5 0
2 years ago
Rewrite 8 and 1/2 as an improper fraction
7nadin3 [17]

8 and 1/2 as an improper fraction is 17/2


To convert an improper fraction to a mixed fraction, follow these steps:

   Divide the numerator by the denominator.

   Write down the whole number answer.

   Then write down any remainder above the denominator.



7 0
3 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
Digiron [165]

Answer:

  • 123 3/11 dm
  • 102 8/11 dm

Step-by-step explanation:

The ratio of the linear dimensions (perimeter) is the square root of the ratio of area dimensions, so the larger : smaller ratio is ...

  √(72/50) = √1.44 = 1.2

The sum of ratio units is 1.2 + 1 = 2.2, so each ratio unit stands for ...

  (226 dm)/2.2 = 102 8/11 dm . . . . . the perimeter of the smaller triangle

Then the perimeter of the larger triangle is ...

  1.2 × 102 8/11 dm = 123 3/11 dm . . . . the perimeter of the larger triangle

6 0
3 years ago
Read 2 more answers
X/7-4=-2 I need to know how to work this problem
galben [10]
X/7-4=-2 u add two to both sides
x/7-2=0you add two to both sides again
x=14 u multiplied 7 and 2 and by x
8 0
3 years ago
An ecological group suspects tuna are consuming dangerous levels of copper in a region of the world. Dangerous levels of copper
Mademuasel [1]

Answer:

Step-by-step explanation:

A) From the stem-leaf plot, we see that out of 21 tunas, 5 have dangerous levels of copper since the levels go beyond 5.7 parts per million. The required proportion is 5/21=0.2381

B) Given the sample mean is {x}=4.77, sample standard deviation s=1.16 and the sample size is n=21.

Since the population standard deviation is not known, we use t-distribution.

So the 98% CI for mean is

4.77 ± t{1-0.02 /2,20} x 1.16/sqrt(21) = (4.13, 5.41)}

We are sure with 98% confidence the true copper level (in parts per million) lies in the interval (4.13, 5.41)

8 0
3 years ago
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