Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
Answer:$133.455
Step-by-step explanation:
2(3x-1) >=4x-6
6x-2>=4x-6
6x-4x>= -6+2
2x>=-4
x>=-2
You can see after simplification, the valve of x can be any number greater than or equal to -2. i.e -5 and -3 can not be in the solution set. the first choice can be dismissed, the fact the variable O could be any number that may not satisfy the solution. Therefore 0-1 is the answer, any thing between 0 & 1 including 0 and one satisfy the solution set
I think it is $60 per day
