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3 years ago

A relation that is symmetric with respect to the x-axis CANNOT be a function,

Mathematics

2 answers:

motikmotik3 years ago

6 0

A function cannot have symmetry with respect to the x-axis

Bas_tet [7]3 years ago

3 0

Answer:

TRUE!!!

Step-by-step explanation:

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Really easy math question

Eddi Din [679]

Number of sodas sold = 130

Number of hot dogs sold = 65

Step-by-step explanation:

Given,

Combined number of sodas and hot dogs sold = 195

Let,

x represent the number of sodas sold

y represent the number of hot dogs sold

According to given statement;

x+y=195 Eqn 1

x = 2y Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$2y+y=195\\3y=195$

Dividing both sides by 3

$\frac{3y}{3}=\frac{195}{3}\\y=65$

Putting y=65 in Eqn 2

$x=2(65)\\x=130$

Number of sodas sold = 130

Number of hot dogs sold = 65

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

4 0

3 years ago

Read 2 more answers

Find the value of c so that the polynomial p(x) is divisible by (x-3). p(x) =-x^3+cx^2-4x+3. c=?

Vilka [71]

Answer:

$\boxed{\textsf {The value of c is $\sf \dfrac{-14}{3}$. }}$

Step-by-step explanation:

A polynomial is given to us . We need to find the value of c so that it is divisible by (x-3 ) .The given polynomial to us is ,

$\sf \implies p(x)=- x^3+cx^2-4x+3$

And the factor is ,

$\sf \implies g(x) = x + 3$

Now , according to factor theorem , p(x) will be divisible by g(x) if p(-3) = 0

$\sf \implies p(x)= - x^3+cx^2-4x+3 \\\\\implies\sf p(-3) = 0 \\\\\sf\implies -(-3)^3+c(-3)^2-4(-3)+3 = 0 \\\\\sf\implies 27 + 9c +12+3=0 \\\\\sf\implies 9c +42=0 \\\\\sf\implies 9c = (-42) \\\\\sf\implies c = \dfrac{-42}{9}\\\\\sf\implies \boxed{\pink{\sf c = \dfrac{-14}{3}}}$