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PSYCHO15rus [73]

3 years ago

10

A charter airline finds that on its Saturday flights from Philadelphia to London all 160 seats will be sold if the ticket price

is $200. However, for each $3 increase in ticket price, the number of seats sold decreases by one.

1 answer:

Bas_tet [7]3 years ago

7 0

Missing part of the question is;

Find a formula for the number of seats sold if the ticket price is P dollars.

Answer:

(680 - P)/3

Step-by-step explanation:

A) Let x be equal to the number of seats and hence we can conclude that (160 - x) is equal to the number of seats after the increase in price.

Similarly, the increase in ticket price would be equal to (P - 200)

Due to the fact that for every $3 increase, the number of seats decrease by 1, the equation that links the change in the number of seats to the change in ticket price is;

P - 200 = 3(160 - x)

P = 3(160 - x) + 200

Making x the subject;

P = 480 - 3x + 200

P = 680 - 3x

3x = 680 - P

x = (680 - P)/3

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We are given that $\theta_1$ is in <em>fourth</em> quadrant.

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Using \theta_1 in place of \theta:

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$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

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So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

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