Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]
Answer:
-48
Step-by-step explanation:
Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square of Mx - Ly. In other words

Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,
- M(x,y) = 4x²y
- Mx(x,y) = 8xy
- L(x,y) = 10y²x
- Ly(x,y) = 20xy
- Mx - Ly = -12xy
Therefore, the line integral can be computed as follows

Using the linearity of the integral and Barrow's Theorem we have

As a result, the value of the double integral is -48-
Liz squeezed lemons faster. Liz squeezed 18 lemons in 6 minutes. To find out how many she squeezed in a minute, you would do 18 / 6, which gives you three. Rick squeezed 24 lemons in 12 minutes. To find out how many lemons he squeezed in a minute, you would do 24/12, which gives you 2. So, Liz squeezed 3 lemons per minute while Rick squeezed 2 lemons per minute.
Let x = the amount that Seini earned
Then x + 25 = the amount that Gavin
The amount Gavin earned would also = 425 - x (your directions asked you to have 2 equations.)
Together they earned 425:
x + (x + 25) = 425
2x + 25 = 425
2x = 400
Now divide both sides by 2 to find x.
Use all of this data to satisfy the directions.
Answer:
If x=1, then f(x)= undefined
Step-by-step explanation:
1*1=1
1-1=0
0/0
You can't divide by 0, so anything that is divided by 0 is undefined.
((1*1)-1)/(1-1)
(1-1)/(1-1)
0/0
0/0=Undefined
f(x)= undefined
Answer:
2.7 in²
Step-by-step explanation:
Area of ∆BAC : ∆Area of EDF = BC² : EF² (based on the area of similar triangles theorem)
Thus:







Area of ∆EDF = 2.7 in²