1.)
10/15 ÷ 5
= 2/3
2.)
7/21 ÷ 7
= 1/3
Given:
∠JEK + ∠DFH = 90°
Find:
relationship, if any, of ∠JEK to angles CFL, HFG, LFE
Solution:
We note that ∠DFG = 90° = ∠DFH + ∠HFG, so ∠JEK ≅∠HFG.
We also note that ∠HFG and ∠CFL are vertical angles, so ∠JEK ≅∠CFL.
And ∠LFE and ∠DFH are vertical angles, so ∠JEK + ∠LFE = 90°.
Evaluating the choices, we find
A) false. The angles are not complementary, they are equal.
B) false. The angles are not equal, they are complementary.
C) false. The angles are not supplementary, they are equal.
D) TRUE. The angles are equal.
The appropriate choice is ...
D) ∠JEK ≅∠CFL
Answer:
Two real number solutions
Step-by-step explanation:
The question is asking "based on the graph, how many times does y=0?"
Then just count how many timesthe graph is on the x-axis.
The answer to your question is 600 and 60
Answer:
0.912
Step-by-step explanation:
<em>The complete question is attached.</em>
<em />
"OR" in probability means "ADDITION". So we find the individual probabilities and "ADD" them.
P(Plan A) would be the total people for plan A (add up column of Plan A) divided by total number of people [add up all the numbers].
Looking at the table, we have:
P (Plan A) = 38/68
Now,
P(40-49 Group) can be found by adding up the row of 40-49 age group and dividing by the total. So, we have:
P(40 - 49 Group) = 24/68
Now, adding up both:
38/68 + 24/68 = 62/68 = 0.912