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4 years ago

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A football team loses 3 yards on one play and 6 yards on another play. Write a sum of negitive integers to represent this situat

ion. find the sum and explain how it is related to the problem

1 answer:

SVETLANKA909090 [29]4 years ago

3 0

-3+-6=-9 -9 is how many yards the football team has lost overall in the two plays

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Where is plymoth rock

Alecsey [184]

Answer:

If u mean plymouth rock then the answer is

Lost at sea, they happened upon a piece of land that would become known as Cape Cod. After surveying the land, they set up camp not too far from Plymouth Rock. ... The 102 travellers aboard the Mayflower landed upon the shores of Plymouth in 1620. This rock still sits on those shores to commemorate the historic event.

Step-by-step explanation:

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3 years ago

What is the measure of AngleDCF? Three lines extend from point C. The space between line C D and C E is 75 degrees. The space be

gizmo_the_mogwai [7]

Answer:

∠DCF = 129°

Step-by-step explanation:

We assume that line CE is between lines CD and CF.

The angle sum theorem applies:

∠DCF = ∠DCE +∠ECF

∠DCF = 75° +54°

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4 years ago

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In 50 gram portion of cereal 8 grams of it are sugar which of the following represents the present of the 50 grams that is sugar

kipiarov [429]

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Step-by-step explanation:

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3 years ago

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A ship sails 250km due North qnd then 150km on a bearing of 075°.1)How far North is the ship now? 2)How far East is the ship now

olga_2 [115]

Answer:

1) 288.8 km due North

2) 144.9 km due East

3) 323.1 km

4) 207°

Step-by-step explanation:

<u>Bearing</u>: The angle (in degrees) measured clockwise from north.

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

<u>Cosine rule</u>

$c^2=a^2+b^2-2ab \cos C$

where a, b and c are the sides and C is the angle opposite side c

-----------------------------------------------------------------------------------------------

Draw a diagram using the given information (see attached).

Create a right triangle (blue on attached diagram).

This right triangle can be used to calculate the additional vertical and horizontal distance the ship sailed after sailing north for 250 km.

<u>Question 1</u>

To find how far North the ship is now, find the measure of the short leg of the right triangle (labelled y on the attached diagram):

$\implies \sf \cos(75^{\circ})=\dfrac{y}{150}$

$\implies \sf y=150\cos(75^{\circ})$

$\implies \sf y=38.92285677$

Then add it to the first portion of the journey:

⇒ 250 + 38.92285677... = 288.8 km

Therefore, the ship is now 288.8 km due North.

<u>Question 2</u>

To find how far East the ship is now, find the measure of the long leg of the right triangle (labelled x on the attached diagram):

$\implies \sf \sin(75^{\circ})=\dfrac{x}{150}$

$\implies \sf x=150\sin(75^{\circ})$

$\implies \sf x=144.8888739$

Therefore, the ship is now 144.9 km due East.

<u>Question 3</u>

To find how far the ship is from its starting point (labelled in red as d on the attached diagram), use the cosine rule:

$\sf \implies d^2=250^2+150^2-2(250)(150) \cos (180-75)$

$\implies \sf d=\sqrt{250^2+150^2-2(250)(150) \cos (180-75)}$

$\implies \sf d=323.1275729$

Therefore, the ship is 323.1 km from its starting point.

<u>Question 4</u>

To find the bearing that the ship is now from its original position, find the angle labelled green on the attached diagram.

Use the answers from part 1 and 2 to find the angle that needs to be added to 180°:

$\implies \sf Bearing=180^{\circ}+\tan^{-1}\left(\dfrac{Total\:Eastern\:distance}{Total\:Northern\:distance}\right)$

$\implies \sf Bearing=180^{\circ}+\tan^{-1}\left(\dfrac{150\sin(75^{\circ})}{250+150\cos(75^{\circ})}\right)$

$\implies \sf Bearing=180^{\circ}+26.64077...^{\circ}$

$\implies \sf Bearing=207^{\circ}$

Therefore, as bearings are usually given as a three-figure bearings, the bearing of the ship from its original position is 207°

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Katena32 [7]

Answer:

a

Step-by-step explanation:

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