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3 years ago

I need help with this

Mathematics

1 answer:

Greeley [361]3 years ago

4 0

Answer:

triangle goes on top

Step-by-step explanation:

i dont know what im doing

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Surface area of a trash can plz show work

ollegr [7]

Answer:

Step-by-step explanation:

So first we need to find the area of the trash can so here is the math:

The formula:

A=LxW

Replace the letters with numbers:

8=2x4

So the area is 8 feet now we can create an equation to solve how much money it would take to make the trash can:

8x0.79=$6.32

It would take $6.32 to make the trash can

6 0

3 years ago

What is −10−f=−6f+10

sammy [17]

-10-f=-6f+10
-f+6f=10+10
5f=20
F=4

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2 years ago

Solve the quadratic equation by factoring-

shtirl [24]

Answer:

c- (2x+3)(x+1)

Step-by-step explanation:

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3 years ago

Please help me out thank you!

ANEK [815]

Answer:

Step-by-step explanation:

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2 years ago

Use the model below to estimate the average annual growth rate of a certain country's population for 1950, 1988, and 2010, where

Morgarella [4.7K]

Answer:

The average annual growth rate of a certain country's population for 1950, 1988, and 2010 are 2.398, 0.9985 and 0.2236 respectively.

Step-by-step explanation:

The given equation is

$Y=-0.0000084x^3+0.00211x^2-0.205x+8.423$

Where Y is the annual growth rate of a certain country's population and x is the number of years after 1900.

Difference between 1950 and 1900 is 50.

Put x=50 in the given equation.

$Y=-0.0000084(50)^3+0.00211(50)^2-0.205(50)+8.423$

$Y=2.398$

Therefore the estimated average annual growth rate of the country's population for 1950 is 2.398.

Difference between 1988 and 1900 is 88.

Put x=88 in the given equation.

$Y=-0.0000084(88)^3+0.00211(88)^2-0.205(88)+8.423$

$Y=0.9984752\approx 0.9985$

Therefore the estimated average annual growth rate of the country's population for 1988 is 0.9985.

Difference between 2010 and 1900 is 110.

Put x=110 in the given equation.

$Y=-0.0000084(110)^3+0.00211(110)^2-0.205(110)+8.423$

$Y=0.2236$

Therefore the estimated average annual growth rate of the country's population for 2010 is 0.2236.

8 0

3 years ago