A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
<h3>
Answer is 0</h3>
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Explanation:
Logarithms are used to solve exponential equations. Specifically if you have a variable in the exponent, then you use a log to isolate the variable.
If we set the given log expression to x, then we can rewrite it into 8^x = 1. The only value of x that works is x = 0.
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Or put another way,
8^x = 1
8^x = 8^0 ... replace the 1 with 8^0
x = 0 ... the bases are equal (to 8) so the exponents must be equal
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You can use the change of base formula to directly calculate this log

Consider the data set shown below. 42, 43, 46, 47, 47, 48, 49, 50, 51, 53, 55, 55, 59 To create a histogram of the data given, i
julia-pushkina [17]
The interval 44-47 has a frequency of 3.The interval 48-51 has a frequency of 4.The interval 56-59 has a frequency of 1.