Question

Khalil is wrapping a cylindrical candle for a gift. The candle is 10 inches tall and has a diameter of 1.5 inches. How many square inches of wrapping paper will Khalil need to cover the candle? Use 3.14 for pi.

Answer 1

The surface area of a cylinder is given as

$A = 2 \pi rh + 2 \pi r^2$

r (radius)= 0.75 since radius is half of the diameter
h (height) = 10

So:
$A = 2 \pi rh + 2 \pi r^2 A = 2 (3.14)(0.75)(10) + 2 (3.14)(0.75)^2 A = 47.1 + 3.5325 A = 50.6325 = 50.63in^2$