Answer:
3
Step-by-step explanation:
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Answer:
L(f(t)) = 
Step-by-step explanation:
let f be a function defined for t ≥ 0
we can write the function f(t) in terms of unit function as follows
f(t) = 2 u,(t) - 1 where
0≤ t < 1
f(t) = (2 * 0) -1 = -1
when t ≥ 1
f(t) = (2*1 )- 1 = 1
Now the Laplace transform L(F(T)) = 2L( u, (t) ) - L(1) --------equation 1
this is because L(u,(t)) = 
c = 1 hence L(1) = 1/s
back to equation 1
L(f(t)) = 2
- 1/s laplace transform
also L(u(t) ) = 
Answer:
x3r9
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
Using Pythagoras theorem,
a^2 = b^2 + c^2
40^2 = 32^2 + c^2
1600 = 1024 + c^2
1600 - 1024 = c^2
576 = c^2
square root of 576 = c
24 = c
9514 1404 393
Answer:
-6
Step-by-step explanation:
Multiply the second equation by 2 and add 6x. You get ...
-6x +y = -6
y = 6x -6
This is the same as the first equation when b = -6. That is what you want if you want infinite solutions.