If the signal had four circular lights, each having the same diameter, what would the total area of all four lights be?

Mathematics

1 answer:

drek231 [11]2 years ago

3 0

Answer:

The answer is " $153.86 \ in^2$ "

Step-by-step explanation:

The circular light which fits around rather than is sufficiently large for fire a camera is indeed a ring light. The ring light provides light with very little darkness, as the bright light is very close to a lens's vertical system. It's also usually called glamour or brightness of beauty.

Let's Each light surface area has $38.465\ in^2$ .

Therefore, the total area of four lights is $38.465 \times 4= 153.86\ in^2$ .

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A company buys orange juice in bulk in containers which hold 25 litres. They sell the juice in cartons which are 8cm by 12cm by

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Answer:

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Step-by-step explanation:

According to the Question,

Given, A company buys orange juice in bulk in containers that hold 25 litres. They sell the juice in cartons which are 8cm by 12cm by 20cm.

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3 years ago

Read 2 more answers

Which is greater 16/12 or 9/3

zavuch27 [327]

Answer:

$\frac{16}{12} \: \: < \frac{9}{3}$

9/3 is greater

Step-by-step explanation:

$\frac{16}{12} \: \: \: \: \: \: \: \: \: \: \frac{9}{3} \\ \frac{16}{12} \: \: \: \: \: \: \: \: \: \: \frac{9 \times 4}{3 \times 4} \\ \frac{16}{12} \: \: \: \: \: \: \: \: \: \: \frac{36}{12} \\ \frac{16}{12} \: < \: \frac{36}{12} \\ \\ so \\ \frac{16}{12} < \frac{9}{3}$