Answer:
a. 54.75
b. 2.64
Step-by-step explanation:
3/5 explanation because I’m big brain boii
Answer:
0.00187393
Hope this helps! :)
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A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
Answer: 0.3125.
Step-by-step explanation:
- The chance of having a boy is 0.5,
- the chance of having a girl is also 0.5.
<u>Outcome 1: all boys</u>
boy boy boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 2: first child is a girl, all others are boys</u>
girl boy boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 3: second child is a girl, all others are boys</u>
boy girl boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 4: third child is a girl, all others are boys</u>
boy boy girl boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 5: fourth child is a girl, all others are boys</u>
boy boy boy girl
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
Therefore,
0.0625 + 0.0625 + 0.0625 + 0.0625 + 0.0625 = 0.0625 * 5 = 0.3125
