We have:
(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1
(30x²+23x+16 - 13)/(cx+3) = 6x+1
(30x²+23x+3)/(cx+3) = 6x+1
30x²+23x+3 = (cx+3)(6x+1)
30x²+23x+3 = 6cx²+cx+18x+3
30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0
(30 - 6c)x² +(5 - c)x = 0
6(5 - c)x² +(5 - c)x = 0
(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.
9514 1404 393
Answer:
280.6 square units
Step-by-step explanation:
The formula for the area of an n-gon with radius r is useful here:
A = (n/2)r²sin(360°/n)
For your hexagon (n=6) with radius r=6√3, the area is ...
A = (6/2)(6√3)²sin(360°/6) = 324sin(60°) = 162√3 ≈ 280.6 . . . square units
Answer: 101 Degrees for angle BCD
Step-by-step explanation: All 3 angles in any triangle add up to 180, in the first triangle (one on the left), you have 58 and 78 degrees, add them both and subtract from 180, you get 44 degrees for angle C on the left. Do the same on the right side of the triangle, you should get 35 degrees for angle C on the right. Add them both up, (35+44) then subtract from 180 degrees to find the measure of angle BCD.
Around 10 of not a clue. Good luck on that!
