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PolarNik [594]
3 years ago
9

What is x if f(x) = -2?

Mathematics
1 answer:
Andrej [43]3 years ago
3 0

<u><em>Answer:</em></u>

<u><em>The answer is 2 or 2x</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>Hope this helps!!</em></u>

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A restaurant charges $3 for a soda and it includes free unlimited
worty [1.4K]
The answer is zero
For each soda you would be the price would go up
The slope is that price that you buy the soda
Except since it is unlimited it means we don’t have to pay for the soda each time we buy one
So every time we buy a soda the price we pay for is not existent
I hope this helps
5 0
3 years ago
Please helppp I am lit begging u I will give you every positive thing on here including brainlest
Solnce55 [7]

Answer:

what do you need help with?

Step-by-step explanation:

IS it math?

4 0
3 years ago
A holiday meal cost 12.50 a person plus a delivery fee of $30 at we cater. The same meal cost $15 a person with no fee at Good E
4vir4ik [10]

Given :

A holiday meal cost 12.50 a person plus a delivery fee of $30 at we cater.

The same meal cost $15 a person with no fee at Good Eats.

To Find :

When does we cater become the better deal.

Solution :

Let , x is number of order .

Cost at cater , C = 12.5x + 30 .

Cost at Good Eats , G = 15x .

We need to find :

G > C

15x>12.5x + 30\\\\2.5x>30\\\\x>12

Therefore, after 12th order cater will be more value for money.

Hence, this is the required solution.

3 0
4 years ago
Is 3z-1 in standard form?
babunello [35]

Answer:

Yes because

Step-by-step explanation:

Is 3z-1 in standard form?

Yes becausestandard form of a polynomial, the value in the power of the variable such as z in the equation reduces from left to right. Therefore, 3z - 1 is in standard form since the z term comes to the left of the constant term

7 0
3 years ago
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
4 years ago
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