$\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=\stackrel{doubled}{2b} \end{cases}\implies A=\cfrac{1}{2}(2b)(h)\implies \stackrel{\textit{twice as the original area}}{A=bh} \\\\[-0.35em] ~\dotfill$

$\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=\stackrel{halved}{\frac{h}{2}} \end{cases}\implies A=\cfrac{1}{2}b\left( \cfrac{h}{2} \right)\implies \stackrel{\textit{half of the original area}}{A=\cfrac{1}{2}bh\left( \cfrac{1}{2} \right)}$

7 0

4 years ago

What is the most basic function

belka [17]

F(x)=x I would say is pretty simple

4 0

3 years ago

A triangle has side lengths measuring 20cm, 5cm, and n cm. Which describes the possible values of n?

igomit [66]

The sum of any two sides must be greater than the third side.

So if n is the largest side:

n<20+5

n<25

And if 20 is the largest side:

n+5>20 subtract 5 from both sides

n>15

Since n>15 and n<25

15<n<25 or in interval notation:

n=(15, 25)

5 0

4 years ago

What is 100000x62728​

What is 100000x62728