![\boxed{pd\sqrt[4]{48p^3d}}](https://tex.z-dn.net/?f=%5Cboxed%7Bpd%5Csqrt%5B4%5D%7B48p%5E3d%7D%7D)
<h2>
Explanation:</h2>
Here we have the following expression:
![\sqrt[4]{48p^7d^5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B48p%5E7d%5E5%7D)
So we need to simplify it:
![\sqrt[4]{48p^7d^5} \\ \\ \\ We \ can \ write: \\ \\ p^7=p^4\cdot p^3 \\ \\ d^5=d^4\cdot d \\ \\ \\ So: \\ \\ \sqrt[4]{48p^4\cdot p^3\cdot d^4\cdot d} \\ \\ \\ By \ property: \\ \\ \sqrt[n]{x^n}=x \\ \\ \\ Finally: \\ \\ \boxed{pd\sqrt[4]{48p^3d}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B48p%5E7d%5E5%7D%20%5C%5C%20%5C%5C%20%5C%5C%20We%20%5C%20can%20%5C%20write%3A%20%5C%5C%20%5C%5C%20p%5E7%3Dp%5E4%5Ccdot%20p%5E3%20%5C%5C%20%5C%5C%20d%5E5%3Dd%5E4%5Ccdot%20d%20%5C%5C%20%5C%5C%20%5C%5C%20So%3A%20%5C%5C%20%5C%5C%20%5Csqrt%5B4%5D%7B48p%5E4%5Ccdot%20p%5E3%5Ccdot%20d%5E4%5Ccdot%20d%7D%20%5C%5C%20%5C%5C%20%5C%5C%20By%20%5C%20property%3A%20%5C%5C%20%5C%5C%20%5Csqrt%5Bn%5D%7Bx%5En%7D%3Dx%20%5C%5C%20%5C%5C%20%5C%5C%20Finally%3A%20%5C%5C%20%5C%5C%20%5Cboxed%7Bpd%5Csqrt%5B4%5D%7B48p%5E3d%7D%7D)
<h2>Learn more:</h2>
Mathematical expressions: brainly.com/question/14200575#
#LearnWithBrainly
Answer:
Step-by-step explanation:
a1 = - 2
an = a1 * r^(n - 1)
a6 = -486
-486 = - 2 * r^(6-1) Divide by 2
243 = r^5
The largest value that r could be is 3.
4^5 = 1024
(243)^(1/5) = 3
So the general formula
an = -2*(3)^(n - 1)
The answer is B because you will cancel the x^5 part on top and bottom and the numerator left 6^3 and denominator left 6
6^3=216divid by 6 you will get 36
Answer:
x=48
Step-by-step explanation:
x-3 15
------------ = ----------
6 2
We can use cross products to solve this problem
(x-3) *2 = 6*15
Distribute
2x-6 = 90
Add 6 to each side
2x-6+6 = 90+6
2x=96
Divide by 2
2x/2 = 96/2
x = 48
Answer:
The answer is 2
Step-by-step explanation:
3/4÷ 3/8 =
3 × 8 * 4 × 3 =
24/12 =
<u>24 ÷ 12</u>
12 ÷ 12 = 2
