The equation 4(x − 7) − 128 = 9x − 5(x + 6) has no solution
<h3><u>Solution:</u></h3>
Given that 4(x − 7) − 128 = 9x − 5(x + 6)
We have to find the solution for this equation
4(x − 7) − 128 = 9x − 5(x + 6)
Let us use BODMAS rule to perform the sequence of operations
According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.
So let us solve for brackets first
4x - 28 - 128 = 9x - 5x - 30
Now let us perform subtraction
4x - 156 = 4x - 30
Now move the terms from R.H.S to L.H.S
4x - 4x = -30 + 156

Since there is no value of x that will ever make this a true statement, the solution to the equation above is “no solution”
So this equation has no solution
Answer:
circumference= 32.56
area= 44.18
Step-by-step explanation:
for area: (A=pi×r^2) your diameter is 7.5 so you divide that by 2 to get your radius. and the radius is 3.75. then you are going to do 3.75^2 to get 14.1 then you are going to multiply 14.1 by pi to get 44.18
for circumference: (2×pi×r) you are going to take the same radius for the area and simply multiply that by pi (3.14) to get 11.78, then you are going to multiply 11.78×2 and that equals 23.56
Answer:
A
Step-by-step explanation:
Answer:
If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.
Step-by-step explanation:
Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.
Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

When we use this to replace the 't" in the displacement formula, we et:

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)
And we can also answer the question about time, since given the same initial velocity
, the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)
Answer:
1. 75%
2. 20%
3. 20%
4. decrease 5.4%
Step-by-step explanation:
1. 119-68=51, 51/68=0.75
2. 30-24=6, 6/30=0.20
3. 18-15=3, 3/15=0.20
4. 762-721=41, 41/762=0.0538