If sin theta = 2/3, which of the following are possible
2 answers:
Sin ø = opposite/hypotenuse = 2/3, cos ø = adjacent/hypotenuse = ?/3, tan ø = opposite/adjacent = 2/?, sec ø = 1/cos ø
to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2
Manipulating the equation to find the adjacent value = ?
adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)
so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>
to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2
Manipulating the equation to find the adjacent value = ?
adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)
so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>
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<span>3x − y = 2
y = 3x - 2
x + y = 6
x + 3x - 2 = 6
4x - 2 = 6
4x = 6 + 2
4x = 8
x = </span>
x = 2
Hence, the x co-ordinate is 2.
y = 3x - 2
x + y = 6
x + 3x - 2 = 6
4x - 2 = 6
4x = 6 + 2
4x = 8
x = </span>
x = 2
Hence, the x co-ordinate is 2.