If sin theta = 2/3, which of the following are possible
2 answers:
Sin ø = opposite/hypotenuse = 2/3, cos ø = adjacent/hypotenuse = ?/3, tan ø = opposite/adjacent = 2/?, sec ø = 1/cos ø
to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2
Manipulating the equation to find the adjacent value = ?
adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)
so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>
to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2
Manipulating the equation to find the adjacent value = ?
adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)
so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>
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Answer: 16) y=-0.5x+3 and 17) y=2x-3
Step-by-step explanation:
16: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.
Since y=3 at x=0, the y-intercept is (0,3), and b=3.
Slope= where (
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Slope==-0.5
Plug m=-0.5 and b=3 into y=mx+b:
y=-0.5x+3
17: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.
Because y=-3 at x=0, the y-intercept is (0,-3), and b=-3.
Slope= where (
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) are two points on the line. Choose (0,-3) and (1,-1):
Slope==
=2
Plug m=2 and b=-3 into y=mx+b:
y=2x-3
Answer:
Step-by-step explanation: