Step-by-step explanation:
f(x) = x² - 3x + 5
f(-2) = (-2)² - 3.(-2) + 5
f(-2) = 4 + 6 + 5
f(-2) = 15
Answer:
<h2>
QS = 42</h2><h2>
</h2>
Step-by-step explanation:
R is midpoint
|<---------------- QS -------------------->|
Q---------------------R--------------------S
8x - 51 3x - 6
find: QS
QR = RS
8x - 51 = 3x - 6
8x - 3x = 51 - 6
5x = 45
x = 45/5
x = 9
QS = QR + RS
QS = (8x - 51) + (3x - 6)
plugin the value of x=9 into the equation above:
QS = (8(9) - 51) + (3(9) - 6)
QS = 72 - 51 + 27 - 6
QS = 42
Answer:
The volume of the figure is ![(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of the figure is equal to the volume of the cone minus the volume of the square pyramid
step 1
Find the volume of the cone
The volume of the cone is equal to

we have
----> the diagonal of the square base of pyramid is equal to the diameter of the cone

substitute

step 2
Find the volume of the square pyramid
The volume of the pyramid is equal to

where
B is the area of the base
h is the height of the pyramid
we have


substitute


step 3
Find the volume of the figure
![\frac{1}{6}\pi (l)^{3}\ units^{3}-\frac{1}{3}l^{3}\ units^{3}=(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cpi%20%28l%29%5E%7B3%7D%5C%20units%5E%7B3%7D-%5Cfrac%7B1%7D%7B3%7Dl%5E%7B3%7D%5C%20units%5E%7B3%7D%3D%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Let's solve this problem step-by-step.
6+0.1x=0.15x+8
Step 1: Simplify both sides of the equation.
0.1x+6=0.15x+8
Step 2: Subtract 0.15x from both sides.
0.1x+6−0.15x=0.15x+8−0.15x
−0.05x+6=8
Step 3: Subtract 6 from both sides.
−0.05x+6−6=8−6
−0.05x=2
Step 4: Divide both sides by -0.05.
-0.05x/-0.05=2/-0.05
So, the answer for this problem is x=-40
Answer:
using the formula x/a + y/b =1
a: slope intercept on the x axis
b:slope intersect on the y axis
x/0 + y/3 = 1 (since x/0 is undefined ,the slope doesn't exist and it is impossible for a slope to be linear)