Question

id="TexFormula1" title="(\frac{v^2-49}{20v^3} )(\frac{4v^2-24v}{v^2+v-42} )" alt="(\frac{v^2-49}{20v^3} )(\frac{4v^2-24v}{v^2+v-42} )" align="absmiddle" class="latex-formula">
I will give brainiest to answer with explanation.
Correct answer is
$\frac{v-7}{5v^2}$

Answer 1

9514 1404 393

Answer:

  (v -7)/(5v^2)

Step-by-step explanation:

Cancel common factors from numerator and denominator.

  $\dfrac{v^2-49}{20v^3}\times\dfrac{4v^2-24v}{v^2+v-42}=\dfrac{4}{20}\cdot\dfrac{(v-7)(v+7)(v)(v-6)}{v^3(v+7)(v-6)}\\\\=\dfrac{1}{5}\cdot\dfrac{v-7}{v^2}\cdot\dfrac{v(v+7)(v-6)}{v(v+7)(v-6)}=\boxed{\dfrac{v-7}{5v^2}}$