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2 years ago

12

Eliza’s backpack weighs 18 7/9 pounds with her math book in it. Without her math book, her backpack weighs 14 ⅞ pounds. How much

does Eliza’s math book weigh?

2 answers:

tigry1 [53]2 years ago

7 0

Answer:

The Eliza's math book weigh = $3\frac{65}{72}$ .

Step-by-step explanation:

We are given that

Eliza's backpack weighs with her math book = $18\frac{7}{9}=\frac{169}{9}$

Eliza's backpack weighs without her math book= $14\frac{7}{8}=\frac{119}{8}$

We have to find the Eliza's math book weigh.

Therefore, we subtract the Eliza's backpack weighs without her math book from the Eliza's backpack weighs with her math book.

Eliza's math book weighs= Eliza's backpack weighs with her math book - Eliza's backpack weighs without her math book

Eliza's math book weighs = $\frac{169}{9}-\frac{119}{8}$

Eliza's math book weighs= $\frac{169\times 8-119\times 9}{72}$

Eliza's math book weighs= $\frac{1352-1071}{72}$

Eliza's math book weighs= $\frac{281}{72}$

Eliza's math book weighs= $3\frac{65}{72}$

Hence, the Eliza's math book weighs= $3\frac{65}{72}$ .

UNO [17]2 years ago

3 0

Make each fraction have a like denominator

7/9 * 8/8= 56/ 72

7/8 * 9/9 = 63/72

18 + 14 + (56+63)/72

32 + 119/72

32 + 1 + 47/72

33 and 47/72

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Answer:

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Step-by-step explanation:

Given equation:

$m=12\ s$

where $m\rightarrow$ number of minutes Lori spends on sketching

and $s\rightarrow$ number of sketches Lori makes.

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So we plugin $s=\frac{3}{4}$ in the equation and calculate $m$ which is time spent by Lori sketching $\frac{3}{4}$ th of a sketch.

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2 years ago

R (-3,1) and S (-1,3) are points on a circle. If RS is a diameter, find the equation of the circle.

ELEN [110]

Answer:

$\sf (x+2)^2+(y-2)^2=2$

Step-by-step explanation:

If RS is the diameter of the circle, then the midpoint of RS will be the center of the circle.

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$\sf \implies r^2=2$

Therefore, the equation of the circle is:

$\sf (x+2)^2+(y-2)^2=2$

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1 year ago

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Step-by-step explanation:

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