Eliza’s backpack weighs 18 7/9 pounds with her math book in it. Without her math book, her backpack weighs 14 ⅞ pounds. How much
2 answers:
Answer:
The Eliza's math book weigh = .
Step-by-step explanation:
We are given that
Eliza's backpack weighs with her math book =
Eliza's backpack weighs without her math book=
We have to find the Eliza's math book weigh.
Therefore, we subtract the Eliza's backpack weighs without her math book from the Eliza's backpack weighs with her math book.
Eliza's math book weighs= Eliza's backpack weighs with her math book - Eliza's backpack weighs without her math book
Eliza's math book weighs =
Eliza's math book weighs=
Eliza's math book weighs=
Eliza's math book weighs=
Eliza's math book weighs=
Hence, the Eliza's math book weighs=.
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Answer:
There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.
Step-by-step explanation:
For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.
And is the probability of X happening.
A probability is said to be unusually low if it is lower than 5%.
For this problem, we have that:
There are 200 reservations, so .
A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So .
Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.
X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find , with
. We can use a binomial probability calculator, and we find that:
.
There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.