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ollegr [7]
2 years ago
7

Open-Ended Write an equation for the line in slope intercept form.​

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
5 0

Answer:

y = -2x+2

Writing the slope was the more difficult part. Writing the y-intercept was the easiest because I had to select to points on the line and solve to get the slope. The y-intercept was already explicitly shown on the line.

Step-by-step explanation:

y = mx+b

y = -2x + 2

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Composite numbers are numbers that are not prime.
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What is the simpler form of (6 + m^2) (6 -m^2)​
PtichkaEL [24]

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=36-m^4

Step-by-step explanation:

8 0
2 years ago
Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660. The sum
Usimov [2.4K]
<span>5t=3b+660....and ... 2t+5b=450

from the first we can see that t=(3b+660)/5 and using this value in the second...

(6b+1320)/5+5b=450 making all have common denominator..

6b+1320+25b=2250

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4 0
3 years ago
Solve the linear programming problem.
larisa [96]

Answer:

1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64

2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21

Step-by-step explanation:

1. Maximize: P = 4x +4y

Subject to: 2x + y ≤ 20

x + 2y ≤ 16

x, y ≥ 0

Plot the constraints and the objective function Z, or P=4x+4y)

Push the objective function to the limit permitted by the feasible region to find the maximum.

Answer: Objective function is a maximum at (16,0),

              Z = 4x+4y = 4(16) + 4(0) = 64

2. Maximize P = 3x + 2y

Subject to x + y ≤ 8

2x + y ≤ 13

x ≥ 0, y ≥ 0

Plot the constraints and the objective function Z, or P=3x+2y.

Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.

Answer: Objective function is at a maximum at (5,3),

              Z = 3x+2y = 3(5)+2(3) = 21

7 0
3 years ago
Please help me answer this
Ronch [10]

Answer:

10.77

Step-by-step explanation:

by using Pythagoras theorem we can find the distance between the points,

so...

distance between the points, which is the hypotenuse will be xy

difference between the y coordinates will be dy

difference between the x coordinates will be dx

according to pythagoras theorem,

xy^{2} = dx^{2} +  dy^{2} \\xy^{2} = (-6-(-2))^{2} + (-5-5)^{2}\\xy^{2} =(-4)^{2} +(-10)^{2} \\xy^{2} =16+100\\xy^{2} =116\\xy =\sqrt{116} \\xy=10.77

8 0
2 years ago
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