24. A total of 540 beads are shared in the ratio 4:5. The LARGER share of beads is

Find the values of x and y. lines that appear to be tangent are tangent

Ket [755]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value of $y = 122^o$

The value of $x = 61^o$

Step-by-step explanation:

Generally the total angle that make up a circle is

$\theta _T = 360$

From the diagram we see that

$\theta _T = y^o + 238^o$

=> $y^o = 360 -238$

$y^o = 122^o$

Generally angle that is formed as a result of interception of a chord and a tangent is equal to the intercepted arc divided by 2

This implies that

$x = \frac{y}{2}$

substituting values

$x = \frac{122}{2}$

$x = 61^o$

4 0

3 years ago

I need to equation for the radius of a 400m running track I know the answer is 36.5 and I know the formula is =2<img src="https:

miskamm [114]

This formula only applies if the track is circular. If it is, then we write the equation:

2*r*pi=400

Dividing by 2pi, we see that:

r=200/pi

This is approximately 63.66.

6 0

3 years ago

Work out the height of a parallelogram with base of 6cm and area of 27cm²

professor190 [17]

To find the height of the parallelogram you would divide 6 from the area, 27, to get the answer 4.5,
So h=4.5

5 0

4 years ago

Evaluate the expression 3c – d for the given variable. d = -c + 7

s2008m [1.1K]

3c-d
3c-(-c+7)
3c+c-7
4c-7
Final answer: 4c-7

5 0

4 years ago

30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now

barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now