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d1i1m1o1n [39]
3 years ago
6

Can you help pls ????

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

What are you trying to ask?

Step-by-step explanation:

faltersainse [42]3 years ago
4 0

Answer:

Fifth box is wrong

Step-by-step explanation:

So they multiply the number infront by itself. 5×5=25 not 32

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What’s 123/17 as a mixed number
svetoff [14.1K]

Answer:

7 4/17

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Write an equation of cosine function with amplitude 2 and a period 4pi
Arisa [49]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}

now.. hmmm let's see, keeping in mind the template above

so, amplitude of 2, A=2, thus |A| = ±2, so, you can use either

and period of 4π, well, that simply means that 

\bf \cfrac{2\pi }{B}=4\pi \implies \cfrac{2\pi }{4\pi }=B\implies \cfrac{1}{2}=B\\\\
-----------------------------\\\\

\begin{array}{llll}
f(\theta)=&\pm 2cos&\left(\frac{1}{2}\theta  \right)\\
&\ \uparrow &\ \uparrow \\
&A&B
\end{array}
8 0
4 years ago
F(x)=(x-2)^2<br><br> Evaluate for f(5)<br><br> Need Answers ASAP
borishaifa [10]

Answer:

<h2>f(5) = 9</h2>

Step-by-step explanation:

f(x) = ( x - 2)²

To find f(5) substitute the value of x that's 5 into f(x). That's for every x in f (x) replace it with 5

That's

f(5) = ( 5 - 2)²

= 3²

We have the final answer as

<h3>f(5) = 9</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
K
vazorg [7]

Answer:

Just to say I am sorry but I got to see the picture to help I am not a reader I am a looker

Step-by-step explanation:

3 0
2 years ago
15. An equilateral triangle has side lengths that
lorasvet [3.4K]

Answer:

a) 3(1.2x - 8) or 3.6x - 24

b)

3(1.2x - 8) = 12

1.2x - 8 = 4

1.2x = 12

x = 12/1.2

= 10

5 0
2 years ago
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