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UNO [17]
3 years ago
14

Select the correct answer.

Mathematics
1 answer:
Semenov [28]3 years ago
3 0

Answer:

The last option: 3 x (7 + 2) = (3 x 7) + (3 x 2)

Step-by-step explanation:

There is addition on the inside, and you are distributing the multiplication from the outside.

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G(x) = 2x^2 and h(x) = .What is (g h)-1 and is it a function?
Andrews [41]
H(x) equals what? I think you've missed that detail. :)
3 0
3 years ago
Read 2 more answers
Factor the expression using the GCF.
ss7ja [257]

Answer:

= 3 (3x + 5y)

Step-by-step explanation:

First find the GCF of 9 and 15 which would be 3. Then the GCF which is 3 is placed on the left of the parentheses. then you plug in the numbers. So 9x divided by 3 is 3x, and 15y divided by 3 is 5y.

7 0
2 years ago
Read 2 more answers
NEED HELP ASAP (WILL GIVD BRAINELST)
Marizza181 [45]

Answer:

5

Step-by-step explanation:

The answer is 60/12 becuase we can simfly both of theese mixed numbers into an improper fraction, wich will be 4/3*15/4. We do the multiplication, and we get 60/12. 60/12 can be simplifed to 5 becuase 60 divided by 12 is 5

6 0
2 years ago
A lamp post with a height of 12 ft casts a shadow of 6 ft. A fire hydrant near it casts a shadow that is 1.5 ft long. How tall i
alex41 [277]

Answer:

3ft

Step-by-step explanation:

We are given that

Height of lamp, h=12ft

Height of shadow, l=6ft

Height of shadow of hydrant, l'=1.5ft

Let height of hydrant=h'

We have to find the height of fire hydrant.

All right triangles are similar

When two triangles are similar then, the ratio of their corresponding sides are equal.

Using the property

\frac{h}{h'}=\frac{l}{l'}

\frac{12}{h'}=\frac{6}{1.5}

h'=\frac{12\times 1.5}{6}

h'=3ft

Hence, the height of fire hydrant=3 ft

3 0
3 years ago
Two teachers purchase supplies for their classrooms.
inna [77]

Answer:

Cost of One Journal =  $3.99

Cost of One pen =  $0.59

Step-by-step explanation:

Let

Cost of One Journal = x

Cost of One pen = y

We can make equation from given statements.

Mr. Bowden purchases 18 journals and 40 pencils for $95.42.

18x+40y=95.42

Ms. Jacinto purchases 11 journals and 16 pencils for $53.33.

11x+16y=53.33

Now solving these equations to find the value of x

18x+40y=95.42--eq(1)\\11x+16y=53.33--eq(2)

Multiply eq(1) with 2 and eq(2) with 5

36x+80y=190.84\\55x+80y=266.65\\-\:\:\:\:-\:\:\:\;\:\:\:\:\:\:\:-\\---------\\-19x=-75.81\\x=\frac{-75.81}{-19}\\x=3.99\\

We get the value of x is: x=3.99

Now, putting value of x in equation 1 to find value of y.

18x+40y=95.42\\18(3.99)+40y=95.42\\71.82+40y=95.42\\40y=95.42-71.82\\40y=23.6\\y=\frac{23.6}{40}\\y= 0.59

So, we get the value of y: y = 0.59

Now, finding the costs:

Cost of One Journal = x = $3.99

Cost of One pen = y = $0.59

7 0
3 years ago
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