Answer:
(-5 , 1)
Step-by-step explanation:
If you are reflecting over the x-axis, you are changing the sign of the y.
If you are reflecting over the y-axis, you are changing the sign of the x.
In this case, you have the point (5 , 1). You are reflecting over the y-axis, which means that you are flipping the sign of the x value.
(5 , 1) reflected over the y-axis is (-5 , 1)
(-5 , 1)
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Answer:
Step-by-step explanation:
We will use the co-function identity for sine, where:
Since sin(21)=0.358=cos(x). This means that:
Solve for x. Add x to both sides:
Subtract 21 from both sides:
Hence:
You can solve for sides of a triangle using the following equation.
A = arccos (b^2 + c^2 - a^2/2bc)
And likewise for other variables by moving the letters.
Ultimately, in this problem you get the following angle measures:
15.87
23.97
140.16
LA=3.5; AY=7
LW=?
LW=LA+AW
AW=?
Let's analyze triangles LAY and YAW
1) Triangle LAY
Angle LAY is 90°
Suppose Angle ALY is x
The angle LYA is the complement of x, for example y:
x+y=90°→y=90°-x
2) Triangle YAW
Angle AYW is the complement of angle LAY (y), then the angle AYW must be equal to x.
Angle YAW is 90°, because the angle LAY is 90°
The triangles LAY and YAW are similars, because they have to congruent angles:
Angle LAY = 90° = Angle YAW
Angle ALY = x = Angle AYW
Then the sides of triangles LAY and YAW must be proportionals:
AW/AY=AY/LA
Replacing the known values:
AW/7=7/3.5
AW/7=2
Solving for AW. Multiplying both sides of the equation by 7:
7(AW/7)=7(2)
AW=14
Now:
LW=LA+AW
LW=3.5+14
LW=17.5
Answer: LW=17.5 units
