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2 years ago

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Which numbers in set A are elements in both the subset of odd numbers and the subset of multiples of 3? Plz help I will give the

brainiest

1 answer:

hodyreva [135]2 years ago

6 0

Only 3 and 9 are both the subset of odd numbers and the subset of multiples of 3.

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Directions: Type the correct answer in each box. Write the coordinates in the form (x, y). If necessary, use / for the fraction

Zanzabum

Answer:

-10.25,-3.75 then the next one is -5.75,-10.75

Step-by-step explanation:

8 0

2 years ago

How many different ways can the line above be named? What are those names?

suter [353]

Its either 3 or 2
the third way matches only if there's another reference line
I'll go with 3

7 0

2 years ago

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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

4 0

2 years ago

Use the maclaurin series for cos(x) to find a maclaurin series for sin^2(x)

kolbaska11 [484]

Try this solution (see the attachment).

5 0

2 years ago

Given the similar triangles shown in the diagram below :

Nesterboy [21]

Answer:

a.) (x-3)(x-3) = 25 + (x-4)(x-4)

x^2 - 6x + 9 = 25 + x^2 - 8x + 16

-6x + 9 = -8x + 41

2x + 9 = 41

2x = 32

x = 16

b.) 16 - 4 = 12

AB = 12

c.) 16 - 3 = 13

AC = 13

[btw I don't know if this is the method your teacher wants as it does not use the similar triangle :/ but it is still correct :) so good luck bro]

6 0

2 years ago

Read 2 more answers