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Korvikt [17]
3 years ago
8

Which numbers in set A are elements in both the subset of odd numbers and the subset of multiples of 3? Plz help I will give the

brainiest
Mathematics
1 answer:
hodyreva [135]3 years ago
6 0

Only 3 and 9 are both the subset of odd numbers and the subset of multiples of 3.

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Is y = -x + 5 non-linear or linear
Lubov Fominskaja [6]

Answer:

It's linear

Step-by-step explanation:

Linear equations have no exponents higher than a 1, which is the case for this equation cause if there's no exponent it's cause it's just a 1. Non-linear has a exponent higher than a 1, ex. x^{2}

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2 years ago
Maria spends $14 on lottery tickets every week and spends $140 month on food.
kozerog [31]
Ten percent is the answer
8 0
3 years ago
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If z=3 and z*y=12 what does y+5 equal
mart [117]
Z = 3                                              (This equation is a given)

z(y) = 12                                       ( This equation is also given) 

3y = 12                                         (as z = 3, plug 3 into z)

3y/3 = 12/3                                   (isolate the y by dividing 3 to both sides) 
                                                  * you divide 3 to both sides because of the equal                                                             sign. What you do to one side you do to the                                                                    other
y = 4                                             (answer for y)

y + 5                                             (what you are solving for)

(4) + 5 = 9                                    (As y = 4, plug in 4 for y in this equation)

y + 5 = 9                                       (4 + 5 =  9, or addition property)

9 is your answer           

hope this helps
5 0
3 years ago
John is choosing a password for his access to the internet. He decided not to use the digit 0 or the letter M. Each letter or nu
mafiozo [28]
25 letters for first spot
25 letters for second spot
25 ^{2} = 625
9 numbers 
9 ^{4} = 6561
6561 times 625
=4,100,625
3 0
3 years ago
$2,500 principal earning 4%, compounded quarterly, after 4 years $40,000.00 $41,600.00 $2,931.45 $2,924.65
AURORKA [14]

Answer:

Amount= $2933.2

Step-by-step explanation:

The interest of $2,500 principal earning with rate of 4%, compounded quarterly, after 4 years

A= p(1+r/n)^(nt)

P= $2500

r= 4/100= 0.04

t= 4

n = 4*4= 16

A= 2500(1+0.04/16)^(16*4)

A= 2500(1+0.0025)^(64)

A= 2500(1.0025)^64

A= 2500(1.17328)

A= 2933.2

Amount= $2933.2

5 0
3 years ago
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