Please help! And thank you!

2. Find f(-1). f(x) = x2-4x+2 X+7 Round your answer to the nearest hundredth.

natka813 [3]

Step-by-step explanation:

$f(x)=\dfrac{x^2-4x+2}{x+7}\\\\f(-1)=\text{put}\ x=-1\ \text{to}\ f(x):\\\\f(-1)=\dfrac{(-1)^2-4(-1)+2}{-1+7}=\dfrac{1+4+2}{6}=\dfrac{7}{6}$

6 0

3 years ago

I need help with letters (D) and (E). My model equation from letter (C) is: P = -55/4 t+ 340.

IceJOKER [234]

Answer:

(a) The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope is m = -55/4

The slope means the rate of decreases of the owl population was 55/4

per year (P decreased by 55/4 each year)

(c) The model equation is P = -55/4 t + 340

(d) The owl population in 2022 will be 216

(e) At year 2038 will be no more owl in the park

Step-by-step explanation:

* Lets explain how to solve the problem

- The owl population in 2013 was measured to be 340

- In 2017 the owl population was measured again to be 285

- The owl population is P and the time is t where t measure the numbers

of years since 2013

(a) Let t represented by the x-coordinates of the order pairs and P

represented by the y-coordinates of the order pairs

∵ t is measured since 2013

∴ At 2013 ⇒ t = 0

∵ The population P in 2013 was 340

∴ The first order pair is (0 , 340)

∵ The time from 2013 to 2013 = 2017 - 2013 = 4 years

∴ At 2017 ⇒ t = 4

∵ The population at 2017 is 285

∴ The second order pair is (4 , 285)

* The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope of any lines whose endpoints are (x1 , y1) and (x2 , y2)

is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

∵ (x1 , y1) is (0 , 340) and (x2 , y2) is (4 , 285)

∴ x1 = 0 , x2 = 4 and y1 = 340 , y2 = 285

∴ $m = \frac{285-340}{4-0}=\frac{-55}{4}$

* The slope is m = -55/4

∵ The slope is negative value

∴ The relation is decreasing

* The slope means the rate of decreases of the owl population was

55/4 per year (P decreased by 55/4 each year)

(c) The linear equation form is y = mx + c, where m is the slope and c is

the value of y when x = 0

∵ The population is P and represented by y

∵ The time is t and represented by t

∴ P = mt + c , c is the initial amount of population

∵ m = -55/4

∵ The initial amount of the population is 340

∴ P = -55/4 t + 340

* The model equation is P = -55/4 t + 340

(d) Lets calculate the time from 2013 to 2022

∵ t = 2022 - 2013 = 9 years

∵ P = -55/4 t + 340

∴ P = -55/4 (9) + 340 = 216.25 ≅ 216

* The owl population in 2022 will be 216

(e) If the model is accurate , then the owl population be be zero after

t years

∵ P = -55/4 t + 340

∵ P = 0

∴ 0 = -55/4 t + 340

- Add 55/4 t to both sides

∴ 55/4 t = 340

- Multiply both sides by 4

∴ 55 t = 1360

- Divide both sides by 55

∴ t = 24.7 ≅ 25 years

- To find the year add 25 years to 2013

∵ 2013 + 25 = 2038

* At year 2038 will be no more owl in the park

8 0

3 years ago

What is y intercept of the continuous in the table?

3241004551 [841]

I’m pretty sure it’s Number 3. Hope I’m Right.

4 0

3 years ago

Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x

Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

Vertex form

$y=a(x-h)^2+k$

(where (h, k) is the vertex)

Given:

vertex = (1, -108)

$\implies y=a(x-1)^2-108$

Given:

y-intercept = (0, -105)

$\implies a(0-1)^2-108=-105$

$\implies a(-1)^2=-105+108$

$\implies a=3$

Therefore:

$\implies y=3(x-1)^2-108$

The x-intercepts are when y = 0

$\implies 3(x-1)^2-108=0$

$\implies 3(x-1)^2=108$

$\implies (x-1)^2=36$

$\implies x-1=\pm \sqrt{36}$

$\implies x=1\pm 6$

$\implies x=7, x=-5$

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0

3 years ago

What is the volume of this rectangular prism 5/2 cm 4 cm 1/2

Naily [24]

Answer:

$5cm ^{3}$

Step-by-step explanation:

$v = whl \\ = \frac{5}{2} \times \frac{4}{1} \times \frac{1}{2} \\ = \frac{20}{4} \\ = 5 {cm}^{3}$

7 0

3 years ago