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3 years ago

7

How to get to standard form from slope intercept?

1 answer:

sweet-ann [11.9K]3 years ago

5 0

The slope intercept form of a linear equation is of the kind y = mx + b.

The standard form of a linear equation is Ax + By = C.

So, to get from y = mx + b to Ax + By = C, you follow these steps:

y - mx = b

=> y + (-m)x = b

=> (-m)x + y = b

For example get the standard form from y = 3x + 5

=> (-3)x + y = 5

where =

A = -3

B = 1

C = 5

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Lines a and b are parallel. Parallel lines a and b are cut by transversals s and t. The angles formed by the intersection of lin

notka56 [123]

Answer:

x = 5

Step-by-step explanation:

Given that, exterior angles on the same side of a traversal are supplementary a Hence, sums up to 180°

Given the angles:

7x° + 11x° + 90° = 180°

18x° + 90° = 180°

18x° = 180° - 90°

18x° = 90°

x = 90° ÷ 18

x = 5

7 0

3 years ago

Read 2 more answers

tatyana61 [14]

Answer: The equation is y= -2x -4

Step-by-step explanation:

The slope intercept form is like y=mx+b so we know the slope which is m but we just need to find the y intercept.

and we will use the given coordinates to find the y intercept by putting in the x and y coordinates into the formula y=mx + b

-6= -2(1) + b

-6= -2 + b

+2 +2

b= -4

5 0

3 years ago

A line passes through the points (2,4) and (5,6) .

Alenkinab [10]

Answer:

Option B and D are correct.

Step-by-step explanation:

Given: A line passes through the points (2,4) and (5,6).

* Case 1:

If a line passes through the points (2, 4) and (5, 6)

Point slope intercept form:

for any two points $(x_1,y_1)$ and $(x_2, y_2)$

then the general form $y -y_1=m(x-x_1)$ for linear equations where m is the slope given by:

$m =\frac{y_2-y_1}{x_2-x_1}$

First calculate slope for the points (2, 4) and (5, 6);

$m = \frac{y_2-y_1}{x_2-x_1} =\frac{6-4}{5-2} = \frac{2}{3}$

then, by point slope intercept form;

$y-4=\frac{2}{3}(x-2)$

* Case 2:

If a line passes through the points (5, 6) and (2, 4)

First calculate slope for the points (5, 6) and (2, 4);

$m = \frac{y_2-y_1}{x_2-x_1} =\frac{4-6}{2-5} = \frac{-2}{-3}= \frac{2}{3}$

then, by point slope intercept form;

$y-6=\frac{2}{3}(x-5)$

Yes, the only equation of line from the given options which describes the given line are;

$y-4=\frac{2}{3}(x-2)$ and $y-6=\frac{2}{3}(x-5)$

8 0

4 years ago

Help me this is the last one I need to do but I'm struggling

Katarina [22]

You would multiply 2 1/2 and 3 3/4, which would give you 9.375 or as a mixed number 9 7/8

3 0

3 years ago

4 EZ GEOMETRY QUESTIONS FOR 20 POINTS!

MatroZZZ [7]

Answer:

1. use the formula

$(n-2)180$

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3 years ago