(3x(a)-6x)- (6a-12) Multiply the outside with the inside
So the rule with multiplying exponents of the same base is
. Apply this rule here:

Next, the rule with converting negative exponents into positive ones is
. Apply this rule here:

<u>Your final answer is 1/49.</u>
<h2>------------------------------------------------</h2>
So an additional rule when it comes to exponents is ![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
In this case, your fractional exponent, x^9/7, would be converted to
. However, I had just realized you can further expand this.
Remember the rule I had mentioned earlier about multiplying exponents of the same base? Well, you can apply it here:
![\sqrt[7]{x^9}=\sqrt[7]{x^7*x^2}=x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7Bx%5E9%7D%3D%5Csqrt%5B7%5D%7Bx%5E7%2Ax%5E2%7D%3Dx%5Csqrt%5B7%5D%7Bx%5E2%7D%20)
Your final answer would be ![x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=%20x%5Csqrt%5B7%5D%7Bx%5E2%7D%20)
Answer:
See solution below
Step-by-step explanation:
According to the diagram shown
m<1 = m<5 = 5=65 degrees (corresponding angle)
m<5 = m<4 - 65 degrees (alternate interior angle)
m<9 = m<8 = 65degrees (corresponding angle)
m<5 = m<8 = 65dgrees (vertically opposite angles)
m<6+m<8 = 180
m<6 + 65 = 180
m<6 = 180 - 65
m<6 = 115degrees
m<2 = m<6 = 115degrees (corresponding angles)
m<6 = m<7 = 115degrees (vertically opposite angles)
m<3 = m<7 = 115degrees(corresponding angle)
)
Step-by-step explanation:
whaaaaaat ........how do we know that
Answer:
A, C
Step-by-step explanation:
Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.
Examining
A) True

Double angle 
B) False,
No further development towards a Trig Identity
C) True
Double Angle Sine Formula 

D) False No further development towards a Trig Identity
![[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)](https://tex.z-dn.net/?f=%5Bsin%28x%29-cos%28x%29%5D%5E%7B2%7D%20%3D1%2Bsin%282x%29%5C%5C%20sin%5E%7B2%7D%20%28x%29-2sin%28x%29cos%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B2sinxcosx%5C%5C%20%5C%5Csin%5E%7B2%7D%20%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B4sin%28x%29cos%28x%29)