Person 1 takes 3 hour 10 minutes to complete 9 procedures
<em><u>Solution:</u></em>
From given question,
Person 2 takes 30 minutes per procedure
Person 1 writes internal operating procedures 3 times faster than Person 2
So we get, Person 1 takes 3 times faster than Person 2
Person 1 takes 10 minutes per procedure
But two of the procedures for Person 1 took an hour each
So person 1 takes 60 minutes each for two of procedures ( since 1 hour = 60 minutes )
<em><u>Calculate how long it took Person 1 to complete 9 procedures:</u></em>
So for first 7 procedures person 1 would take 10 minutes per procedure and for last two procedures person 1 would take 60 minutes per procedure
![time $=7$ procedures $\times \frac{10 \text { minutes }}{1 \text { procedure }}+2$ procedure $\times \frac{60 \text { minutes }}{1 \text { procedure }}$](https://tex.z-dn.net/?f=time%20%24%3D7%24%20procedures%20%24%5Ctimes%20%5Cfrac%7B10%20%5Ctext%20%7B%20minutes%20%7D%7D%7B1%20%5Ctext%20%7B%20procedure%20%7D%7D%2B2%24%20procedure%20%24%5Ctimes%20%5Cfrac%7B60%20%5Ctext%20%7B%20minutes%20%7D%7D%7B1%20%5Ctext%20%7B%20procedure%20%7D%7D%24)
![time=70 minutes +120minutes\\\\time=190minutes](https://tex.z-dn.net/?f=time%3D70%20minutes%20%2B120minutes%5C%5C%5C%5Ctime%3D190minutes)
We know that,
1 hour = 60 minutes
Therefore,
190 minutes = 60 minutes + 60 minutes + 60 minutes + 10 minutes
190 minutes = 1 hour + 1 hour + 1 hour + 10 minutes = 3 hour 10 minutes
Therefore Person 1 takes 3 hour 10 minutes to complete 9 procedures
N= 0.8
this is the answer to ur problem
Answer:
![\frac{2}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B25%7D)
Step-by-step explanation:
Given expression,
![\frac{\frac{2x-4}{30} }{\frac{15x-30}{18} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B2x-4%7D%7B30%7D%20%7D%7B%5Cfrac%7B15x-30%7D%7B18%7D%20%7D)
=>![\frac{\frac{2(x-2)}{30} }{\frac{15(x-2)}{18} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B2%28x-2%29%7D%7B30%7D%20%7D%7B%5Cfrac%7B15%28x-2%29%7D%7B18%7D%20%7D)
We see that
is common in both numerator and denominator
hence canceling out we get:-
![\frac{2*18}{30*15}=\frac{2}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B2%2A18%7D%7B30%2A15%7D%3D%5Cfrac%7B2%7D%7B25%7D)
Answer=![\frac{2}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B25%7D)
Answer:
4 mph?
Step-by-step explanation:
Answer:
Part 1
Given equation:
C(t) = -0.30 (t – 12)² + 40
For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2
For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40
For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2
Part 2
attached below
Part 3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32
Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104
5, 6 and 7, should be simplish
good luck, i hope this helps :)
Step-by-step explanation: